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A population is growing logistically with a growth rate of 0.15 /week. The maximum growth rate of this population, if carrying capacity of the environment is 400 individuals will be ____________
[Answer upto one decimal place]
    Correct answer is between '14.5,15.5'. Can you explain this answer?
    Verified Answer
    A population is growing logistically with a growth rate of 0.15 /week....
    Maximum population growth of a population happen at half of the carrying capacity.
    So, at maximum population growth period the size of the population should be 400/2=200 individuals.
    So, the formula for logistic population growth is  dN/dt= rN ( 1 – N/K)
    dn/dt = 0.15 × 200 (1 – 200/400)
    = 0.15 × 200 (0.5)
    = 0.15 × 100
    = 15 individuals per week
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    A population is growing logistically with a growth rate of 0.15 /week....
    Introduction:
    The logistic growth model is a mathematical model that describes how a population grows over time. It takes into account both the growth rate and the carrying capacity of the environment. In this question, we are given a growth rate of 0.15 individuals per week and a carrying capacity of 400 individuals. We need to determine the maximum growth rate of the population.

    Understanding the Logistic Growth Model:
    The logistic growth model is based on the assumption that as the population size increases, the availability of resources becomes limited, leading to a decrease in the growth rate. Eventually, the population reaches a point where the growth rate becomes zero, called the carrying capacity.

    The logistic growth model can be expressed mathematically as:

    dN/dt = rN * (1 - N/K)

    where:
    dN/dt is the rate of change of population over time,
    r is the intrinsic growth rate,
    N is the population size, and
    K is the carrying capacity.

    Determining the Maximum Growth Rate:
    In order to determine the maximum growth rate, we need to find the value of r that results in the maximum population growth. This occurs when the rate of change of population is at its peak.

    To find the maximum growth rate, we can take the derivative of the logistic growth equation with respect to N and set it equal to zero:

    dN/dt = rN * (1 - N/K)
    dN/dt = r - (rN/K) - (rN^2 / K)

    Setting dN/dt equal to zero and solving for N:

    0 = r - (rN/K) - (rN^2 / K)
    0 = r - (rN/K) - (rN^2 / K)

    Simplifying the equation:

    0 = r - 2rN/K - (rN^2 / K)

    Since we are given the carrying capacity K = 400, we can substitute this value into the equation:

    0 = r - 2rN/400 - (rN^2 / 400)

    Simplifying further:

    0 = r - (2rN + rN^2) / 400

    We can rearrange the equation to find the values of N where the growth rate is zero:

    r = (2rN + rN^2) / 400
    400r = 2rN + rN^2
    rN^2 + 2rN - 400r = 0

    This is a quadratic equation in terms of N. Solving this equation will give us the values of N where the growth rate is zero. The maximum growth rate occurs when the population size is between these two values.

    Conclusion:
    To determine the maximum growth rate of the population, we need to solve the quadratic equation derived from the logistic growth model. The solution will give us the values of N where the growth rate is zero. The maximum growth rate occurs when the population size is between these two values. In this case, the correct answer is between 14.5 and 15.5.
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    A population is growing logistically with a growth rate of 0.15 /week. The maximum growth rate of this population, if carrying capacity of the environment is 400 individuals will be ____________[Answer upto one decimal place]Correct answer is between '14.5,15.5'. Can you explain this answer?
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    A population is growing logistically with a growth rate of 0.15 /week. The maximum growth rate of this population, if carrying capacity of the environment is 400 individuals will be ____________[Answer upto one decimal place]Correct answer is between '14.5,15.5'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A population is growing logistically with a growth rate of 0.15 /week. The maximum growth rate of this population, if carrying capacity of the environment is 400 individuals will be ____________[Answer upto one decimal place]Correct answer is between '14.5,15.5'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A population is growing logistically with a growth rate of 0.15 /week. The maximum growth rate of this population, if carrying capacity of the environment is 400 individuals will be ____________[Answer upto one decimal place]Correct answer is between '14.5,15.5'. Can you explain this answer?.
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