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Three acidic solutions A, B and C contain acid and water in the ratio 4 : 1,5 : 3 and 1 : 1 respectively. A mixture solution of the three contains solution A to solutions B and C collectively in the ratio 3 : 2. If the concentration of the acid in the mixture solution is 70% then find the ratio in which the three mixtures has been added.
- a)10 : 4 : 6
- b)15 : 4 : 6
- c)12 : 8 : 6
- d)18 :10 :9
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Three acidic solutions A, B and C contain acid and water in the ratio ...
A : (B + C) = 3 : 2
C onsider option 1:
A:B:C = 10:4:6 ⇒ A:(B + C) = 1 : 1
Thus, option 1 can be eliminated.
Consider option 2:
A:B:C = 15:4:6⇒A:(B + C) = 3 : 2
Thus, option 2 can be the answer option.
Consider option 3:
A:B:C = 12:8:6 ⇒ A:(B + C) = 6 : 7
Thus, option 3 can be eliminated.
Consider option 4:
A : B : C = 18 : 10 : 9 ⇒ A : (B + C) = 18 : 19
Thus, option 4 can be eliminated.
Hence, option 2.
C onsider option 1:
A:B:C = 10:4:6 ⇒ A:(B + C) = 1 : 1
Thus, option 1 can be eliminated.
Consider option 2:
A:B:C = 15:4:6⇒A:(B + C) = 3 : 2
Thus, option 2 can be the answer option.
Consider option 3:
A:B:C = 12:8:6 ⇒ A:(B + C) = 6 : 7
Thus, option 3 can be eliminated.
Consider option 4:
A : B : C = 18 : 10 : 9 ⇒ A : (B + C) = 18 : 19
Thus, option 4 can be eliminated.
Hence, option 2.
Most Upvoted Answer
Three acidic solutions A, B and C contain acid and water in the ratio ...
To solve this question, let's first calculate the composition of each solution A, B, and C.
Given:
Ratio of acid to water in solution A = 4:1
Ratio of acid to water in solution B = 5:3
Ratio of acid to water in solution C = 1:1
Based on these ratios, we can calculate the concentration of acid in each solution.
Solution A:
Let the quantity of acid in solution A be 4x and the quantity of water be x.
So, the concentration of acid in solution A = (4x / (4x + x)) * 100% = 80%
Solution B:
Let the quantity of acid in solution B be 5y and the quantity of water be 3y.
So, the concentration of acid in solution B = (5y / (5y + 3y)) * 100% = 62.5%
Solution C:
Let the quantity of acid in solution C be z and the quantity of water be z.
So, the concentration of acid in solution C = (z / (z + z)) * 100% = 50%
Next, let's consider the mixture solution of A, B, and C.
Given:
Ratio of A to (B + C) = 3:2
Concentration of acid in the mixture solution = 70%
Let the quantity of the mixture solution be M.
From the ratio, we can say that the quantity of solution A in the mixture = (3/5) * M
The quantity of solution B + C in the mixture = (2/5) * M
Now, let's calculate the concentration of acid in the mixture solution.
Concentration of acid in the mixture solution = [(concentration of acid in A * quantity of A) + (concentration of acid in B + C * quantity of B + C)] / (quantity of A + quantity of B + C)
70% = [(80% * (3/5) * M) + (62.5% * (2/5) * M)] / M
Simplifying this equation, we get:
0.7 = (0.48 + 0.25) / 1
0.7 = 0.73
This is not possible, so there is an error in the question or options provided. Please check the question again or provide the correct options.
Given:
Ratio of acid to water in solution A = 4:1
Ratio of acid to water in solution B = 5:3
Ratio of acid to water in solution C = 1:1
Based on these ratios, we can calculate the concentration of acid in each solution.
Solution A:
Let the quantity of acid in solution A be 4x and the quantity of water be x.
So, the concentration of acid in solution A = (4x / (4x + x)) * 100% = 80%
Solution B:
Let the quantity of acid in solution B be 5y and the quantity of water be 3y.
So, the concentration of acid in solution B = (5y / (5y + 3y)) * 100% = 62.5%
Solution C:
Let the quantity of acid in solution C be z and the quantity of water be z.
So, the concentration of acid in solution C = (z / (z + z)) * 100% = 50%
Next, let's consider the mixture solution of A, B, and C.
Given:
Ratio of A to (B + C) = 3:2
Concentration of acid in the mixture solution = 70%
Let the quantity of the mixture solution be M.
From the ratio, we can say that the quantity of solution A in the mixture = (3/5) * M
The quantity of solution B + C in the mixture = (2/5) * M
Now, let's calculate the concentration of acid in the mixture solution.
Concentration of acid in the mixture solution = [(concentration of acid in A * quantity of A) + (concentration of acid in B + C * quantity of B + C)] / (quantity of A + quantity of B + C)
70% = [(80% * (3/5) * M) + (62.5% * (2/5) * M)] / M
Simplifying this equation, we get:
0.7 = (0.48 + 0.25) / 1
0.7 = 0.73
This is not possible, so there is an error in the question or options provided. Please check the question again or provide the correct options.
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Three acidic solutions A, B and C contain acid and water in the ratio 4 : 1,5 : 3 and 1 : 1 respectively. A mixture solution of the three contains solution A to solutions B and C collectively in the ratio 3 : 2. If the concentration of the acid in the mixture solution is 70% then find the ratio in which the three mixtures has been added.a)10 : 4 : 6b)15 : 4 : 6c)12 : 8 : 6d)18 :10 :9Correct answer is option 'B'. Can you explain this answer?
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