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A boy went to his school at a speed of 12 km/h and returned to his house at a speed of 8 km/h. If he has taken 50 minutes for the whole journey, what was the total distance walked?
  • a)
    4 km
  • b)
    8 km
  • c)
    16 km
  • d)
    20 km
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A boy went to his school at a speed of 12 km/h and returned to his hou...
Let the distant between his school and house be ‘x’
Total time taken = Time taken from school to house + Time taken from house to school
50/60 h = x/12 + x/8 [∵ Speed = Distance/time]
50/60 = (2x + 3x) /24
50/60 = 5x/24
∴ x = 4 kms
∴ Total distance walked = 2x = 8 kms
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Most Upvoted Answer
A boy went to his school at a speed of 12 km/h and returned to his hou...
Let's first calculate the time it took for the boy to go to school and return home separately.

Going to school:
- Speed = 12 km/h
- Let the distance to school be 'd' km
- Time taken = distance/speed = d/12 hours

Returning home:
- Speed = 8 km/h
- Distance is the same as going to school, 'd' km.
- Time taken = distance/speed = d/8 hours

The total time taken for the whole journey is given as 50 minutes, which is equal to 50/60 = 5/6 hours.

So, we can write the equation:
d/12 + d/8 = 5/6

To solve this equation, we can find the common denominator of 12 and 8, which is 24:

2d/24 + 3d/24 = 5/6

Combining the terms with the same denominator, we get:
(2d + 3d)/24 = 5/6

Simplifying the equation further:
5d/24 = 5/6

Cross-multiplying:
6 * 5d = 5 * 24

30d = 120

Dividing both sides by 30:
d = 4

Therefore, the distance to school and back is 4 km each. The total distance walked is the sum of these two distances, which is 4 + 4 = 8 km.

Hence, the correct answer is option B) 8 km.
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A boy went to his school at a speed of 12 km/h and returned to his house at a speed of 8 km/h. If he has taken 50 minutes for the whole journey, what was the total distance walked?a)4 kmb)8 kmc)16 kmd)20 kmCorrect answer is option 'B'. Can you explain this answer?
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