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Find equations for the tangent plane to the surface z = x2 + y2 at the point (2, -1, 5).
  • a)
    Tangent plane ⇒ 4x - 2y - z = 5
  • b)
    Tangent plane ⇒ 4x + 2y - z = 5
  • c)
    Tangent plane ⇒ 4x - 2y + z = 5
  • d)
    Tangent plane ⇒ -4x - 2y - z = 5
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Find equations for the tangent plane to the surface z = x2 + y2 at the...
Surface z = x2 + y2
⇒ surface S = x2 + y2 - z = 0 
hence
  (1)
the equation of a plane, passing through a point whose position vector is r0 and which is perpendicular to the normal N 
(r - r0).N = 0
then the required equation is
⇒ 4(x - 2) - 2(y + 1) - 1 (z - 5) = 0
⇒ 4 x - 8 - 2 y - 2 - z + 5 = 0
⇒ 4x - 2y - z = 5
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Most Upvoted Answer
Find equations for the tangent plane to the surface z = x2 + y2 at the...
To find the equation of the tangent plane to the surface z = x^2 * y^2 at the point (2, -1, 5), we first need to find the partial derivatives of z with respect to x and y.

∂z/∂x = 2xy^2
∂z/∂y = 2x^2y

Next, we evaluate these partial derivatives at the point (2, -1, 5):

∂z/∂x = 2(2)(-1)^2 = 4
∂z/∂y = 2(2^2)(-1) = -8

The equation of the tangent plane can then be written as:

z - z0 = ∂z/∂x * (x - x0) + ∂z/∂y * (y - y0)

Where (x0, y0, z0) is the given point (2, -1, 5).

Plugging in the values:

z - 5 = 4(x - 2) - 8(y - (-1))

Simplifying:

z - 5 = 4x - 8 - 8y + 8

Rearranging the terms:

4x - 8y + z = 1

Therefore, the equation of the tangent plane is 4x - 8y + z = 1.
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Find equations for the tangent plane to the surface z = x2 + y2 at the point (2, -1, 5).a)Tangent plane ⇒ 4x - 2y - z = 5b)Tangent plane ⇒ 4x + 2y - z = 5c)Tangent plane ⇒ 4x - 2y + z = 5d)Tangent plane ⇒ -4x - 2y - z = 5Correct answer is option 'A'. Can you explain this answer?
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Find equations for the tangent plane to the surface z = x2 + y2 at the point (2, -1, 5).a)Tangent plane ⇒ 4x - 2y - z = 5b)Tangent plane ⇒ 4x + 2y - z = 5c)Tangent plane ⇒ 4x - 2y + z = 5d)Tangent plane ⇒ -4x - 2y - z = 5Correct answer is option 'A'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about Find equations for the tangent plane to the surface z = x2 + y2 at the point (2, -1, 5).a)Tangent plane ⇒ 4x - 2y - z = 5b)Tangent plane ⇒ 4x + 2y - z = 5c)Tangent plane ⇒ 4x - 2y + z = 5d)Tangent plane ⇒ -4x - 2y - z = 5Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find equations for the tangent plane to the surface z = x2 + y2 at the point (2, -1, 5).a)Tangent plane ⇒ 4x - 2y - z = 5b)Tangent plane ⇒ 4x + 2y - z = 5c)Tangent plane ⇒ 4x - 2y + z = 5d)Tangent plane ⇒ -4x - 2y - z = 5Correct answer is option 'A'. Can you explain this answer?.
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