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A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from the point O. After one second, the elevation of the bird from O is reduced to 30°. Then the speed (in m/s) of the bird is
- a)20√2
- b)20 (√3 − 1)
- c)40(√2 − 1)
- d)40(√3 − √2)
Correct answer is option 'B'. Can you explain this answer?
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To solve this problem, we can use trigonometry.
Let's consider a right triangle formed by the bird, the top of the pole, and the point O on the ground. The vertical pole acts as the height of the triangle, which is 20 m. The bird's elevation from point O is the angle opposite to the height.
We know that the tangent of an angle is equal to the ratio of the opposite side (height) to the adjacent side (distance from the bird to point O).
Using the tangent function, we can write:
tan(45°) = height / distance from bird to point O
Substituting the known values, we have:
tan(45°) = 20 / distance from bird to point O
Now, we can solve for the distance from the bird to point O:
distance from bird to point O = 20 / tan(45°)
Using a calculator, we find:
distance from bird to point O ≈ 20 / 1
distance from bird to point O ≈ 20 m
Therefore, the distance from the bird to point O on the ground is approximately 20 meters.
Let's consider a right triangle formed by the bird, the top of the pole, and the point O on the ground. The vertical pole acts as the height of the triangle, which is 20 m. The bird's elevation from point O is the angle opposite to the height.
We know that the tangent of an angle is equal to the ratio of the opposite side (height) to the adjacent side (distance from the bird to point O).
Using the tangent function, we can write:
tan(45°) = height / distance from bird to point O
Substituting the known values, we have:
tan(45°) = 20 / distance from bird to point O
Now, we can solve for the distance from the bird to point O:
distance from bird to point O = 20 / tan(45°)
Using a calculator, we find:
distance from bird to point O ≈ 20 / 1
distance from bird to point O ≈ 20 m
Therefore, the distance from the bird to point O on the ground is approximately 20 meters.
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A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from the point O. After one second, the elevation of the bird from O is reduced to 30°. Then the speed (in m/s) of the bird isa)20√2b)20 (√3 − 1)c)40(√2 − 1)d)40(√3 − √2)Correct answer is option 'B'. Can you explain this answer?
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A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from the point O. After one second, the elevation of the bird from O is reduced to 30°. Then the speed (in m/s) of the bird isa)20√2b)20 (√3 − 1)c)40(√2 − 1)d)40(√3 − √2)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from the point O. After one second, the elevation of the bird from O is reduced to 30°. Then the speed (in m/s) of the bird isa)20√2b)20 (√3 − 1)c)40(√2 − 1)d)40(√3 − √2)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from the point O. After one second, the elevation of the bird from O is reduced to 30°. Then the speed (in m/s) of the bird isa)20√2b)20 (√3 − 1)c)40(√2 − 1)d)40(√3 − √2)Correct answer is option 'B'. Can you explain this answer?.
A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from the point O. After one second, the elevation of the bird from O is reduced to 30°. Then the speed (in m/s) of the bird isa)20√2b)20 (√3 − 1)c)40(√2 − 1)d)40(√3 − √2)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from the point O. After one second, the elevation of the bird from O is reduced to 30°. Then the speed (in m/s) of the bird isa)20√2b)20 (√3 − 1)c)40(√2 − 1)d)40(√3 − √2)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from the point O. After one second, the elevation of the bird from O is reduced to 30°. Then the speed (in m/s) of the bird isa)20√2b)20 (√3 − 1)c)40(√2 − 1)d)40(√3 − √2)Correct answer is option 'B'. Can you explain this answer?.
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