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Euler's formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:
[IES-1998]
- a)Effect of direct stress is neglected
- b)Pin joints are not free from friction
- c)The assumptions made in using the formula are not met in practice
- d)The material does not behave in an ideal elastic way in tension and compression
Correct answer is option 'C'. Can you explain this answer?
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Eulers formula gives 5 to 10% error in crippling load as compared to e...
Explanation:
Euler's formula is a theoretical formula used to calculate the critical buckling load of a long, slender column under an axial compressive load. However, in practical situations, the formula may not give accurate results due to the following reasons:
1. Assumptions made in using the formula: Euler's formula assumes that the column is perfectly straight, homogeneous, isotropic, and has a constant cross-section throughout its length. However, in practice, these assumptions may not hold true, and the actual column may have imperfections, non-uniformities, and variations in cross-section, which can affect the critical buckling load.
2. Effect of direct stress is neglected: Euler's formula only considers the effect of compressive stress on the column, and neglects the effect of any other stresses, such as tensile or shear stresses, which may also contribute to the failure of the column.
3. Pin joints are not free from friction: Euler's formula assumes that the pin joints connecting the column to its supports are perfectly free to rotate without any friction. However, in practice, pin joints may have some friction, which can affect the critical buckling load.
4. Material does not behave in an ideal elastic way in tension and compression: Euler's formula assumes that the material of the column behaves in an ideal elastic way under both tension and compression. However, in practice, the material may not behave in this ideal way, and may exhibit plastic deformation, creep, or other non-elastic behaviors, which can affect the critical buckling load.
Conclusion:
Due to these factors, Euler's formula may give an error of 5 to 10% when compared to experimental results in practice. Therefore, it is important to consider these factors and use appropriate correction factors or more accurate analytical or numerical methods to calculate the critical buckling load of columns in practical situations.
Euler's formula is a theoretical formula used to calculate the critical buckling load of a long, slender column under an axial compressive load. However, in practical situations, the formula may not give accurate results due to the following reasons:
1. Assumptions made in using the formula: Euler's formula assumes that the column is perfectly straight, homogeneous, isotropic, and has a constant cross-section throughout its length. However, in practice, these assumptions may not hold true, and the actual column may have imperfections, non-uniformities, and variations in cross-section, which can affect the critical buckling load.
2. Effect of direct stress is neglected: Euler's formula only considers the effect of compressive stress on the column, and neglects the effect of any other stresses, such as tensile or shear stresses, which may also contribute to the failure of the column.
3. Pin joints are not free from friction: Euler's formula assumes that the pin joints connecting the column to its supports are perfectly free to rotate without any friction. However, in practice, pin joints may have some friction, which can affect the critical buckling load.
4. Material does not behave in an ideal elastic way in tension and compression: Euler's formula assumes that the material of the column behaves in an ideal elastic way under both tension and compression. However, in practice, the material may not behave in this ideal way, and may exhibit plastic deformation, creep, or other non-elastic behaviors, which can affect the critical buckling load.
Conclusion:
Due to these factors, Euler's formula may give an error of 5 to 10% when compared to experimental results in practice. Therefore, it is important to consider these factors and use appropriate correction factors or more accurate analytical or numerical methods to calculate the critical buckling load of columns in practical situations.
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Eulers formula gives 5 to 10% error in crippling load as compared to e...
The effect of direct stress in the euler formula is neglected
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Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer?
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Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer?.
Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer?.
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Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Eulers formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:[IES-1998]a)Effect of direct stress is neglectedb)Pin joints are not free from frictionc)The assumptions made in using the formula are not met in practiced)The material does not behave in an ideal elastic way in tension and compressionCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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