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Find the total no. of proper subgroups of a cyclic group G = [ a ] of order 40.
    Correct answer is '6'. Can you explain this answer?
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    Find the total no. of proper subgroups of a cyclic group G = [ a ] of ...
    By lagrange theorem we know that, If G be a group and H be a subgroup of group G , then order of H divides order of G.
    Hence all the divisors of 40 are order of subgroup of group G.
    All the divisors are → 1 , 2 , 4 , 5 , 8 , 1 0 , 2 0 , 4 0 but order 1 and order 40 are improper subgroup of group G , Hence total proper subgroup are 6.
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    Find the total no. of proper subgroups of a cyclic group G = [ a ] of ...
    By lagrange theorem we know that, If G be a group and H be a subgroup of group G , then order of H divides order of G.
    Hence all the divisors of 40 are order of subgroup of group G.
    All the divisors are → 1 , 2 , 4 , 5 , 8 , 1 0 , 2 0 , 4 0 but order 1 and order 40 are improper subgroup of group G , Hence total proper subgroup are 6.
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    Find the total no. of proper subgroups of a cyclic group G = [ a ] of order 40.Correct answer is '6'. Can you explain this answer?
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    Find the total no. of proper subgroups of a cyclic group G = [ a ] of order 40.Correct answer is '6'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about Find the total no. of proper subgroups of a cyclic group G = [ a ] of order 40.Correct answer is '6'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the total no. of proper subgroups of a cyclic group G = [ a ] of order 40.Correct answer is '6'. Can you explain this answer?.
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