Distance from point charge, r = 1m

Intensity of electric field, E = 450 NC^-1


Magnitude of the charge, q


Electric field intensity, E = k(q/r^2)

where k is Coulomb's constant = 9 x 10^9 Nm^2/C^2


Substituting the given values in the formula, we get:

450 = (9 x 10^9)q/1^2

450 = 9 x 10^9 q

q = 450/(9 x 10^9)

q = 5 x 10^-8 C


Therefore, the magnitude of the charge is 5 x 10^-8 C.


- The electric field intensity at a distance from a point charge is given by the formula E = k(q/r^2), where k is Coulomb's constant, q is the magnitude of the charge and r is the distance from the point charge.
- In the given problem, we are given the distance from the point charge and the electric field intensity. Hence, we can use the formula to calculate the magnitude of the charge.
- After substituting the given values in the formula and solving for q, we get the magnitude of the charge as 5 x 10^-8 C.
- This means that if there is a point charge of magnitude 5 x 10^-8 C at a distance of 1m, the electric field intensity at that point would be 450 NC^-1.