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An unscrupulous shopkeeper buys a certain amount of salt at mixes it with white sand so as to earn more profit. The white sand is available free of cost and the two are mixed in equal quantity of weight. Find the percentage profit/loss in selling the adulterated salt if he claims to sell it at 10% loss.
- a)25% profit
- b)80% profit
- c)25% loss
- d)80% loss
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
An unscrupulous shopkeeper buys a certain amount of salt at mixes it w...
Let the cost price of salt be Rs. x per kg.
The cost price of 2 kg salt will be Rs. 2x
The shopkeeper sells it at 2 * x * 0.9 = 1.8x
But the shopkeeper gets it for Rs. x only
Hence, option 2.
The cost price of 2 kg salt will be Rs. 2x
The shopkeeper sells it at 2 * x * 0.9 = 1.8x
But the shopkeeper gets it for Rs. x only
Hence, option 2.
Most Upvoted Answer
An unscrupulous shopkeeper buys a certain amount of salt at mixes it w...
Calculation of Profit/Loss in Selling Adulterated Salt:
Given Data:
- Shopkeeper mixes equal weight of salt and white sand.
- Shopkeeper claims to sell the mixture at a 10% loss.
Calculations:
1. Let us assume that the cost price of 1 kg of salt is $100.
2. Shopkeeper mixes 1 kg of salt with 1 kg of white sand.
3. Total cost price of the mixture = Cost of salt + Cost of sand = $100 + $0 = $100.
4. Selling price of the mixture at a 10% loss = 90% of $100 = $90.
5. Profit/Loss = Selling price - Cost price = $90 - $100 = -$10 (Loss).
Percentage Profit/Loss:
- Percentage Profit/Loss = (Profit/Loss / Cost Price) x 100
- Percentage Profit/Loss = (-$10 / $100) x 100 = -10%
Conclusion:
- The shopkeeper incurs a 10% loss in selling the adulterated salt.
- To calculate the percentage profit/loss in selling the adulterated salt, we need to consider the actual cost price and selling price of the mixture.
Given Data:
- Shopkeeper mixes equal weight of salt and white sand.
- Shopkeeper claims to sell the mixture at a 10% loss.
Calculations:
1. Let us assume that the cost price of 1 kg of salt is $100.
2. Shopkeeper mixes 1 kg of salt with 1 kg of white sand.
3. Total cost price of the mixture = Cost of salt + Cost of sand = $100 + $0 = $100.
4. Selling price of the mixture at a 10% loss = 90% of $100 = $90.
5. Profit/Loss = Selling price - Cost price = $90 - $100 = -$10 (Loss).
Percentage Profit/Loss:
- Percentage Profit/Loss = (Profit/Loss / Cost Price) x 100
- Percentage Profit/Loss = (-$10 / $100) x 100 = -10%
Conclusion:
- The shopkeeper incurs a 10% loss in selling the adulterated salt.
- To calculate the percentage profit/loss in selling the adulterated salt, we need to consider the actual cost price and selling price of the mixture.
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An unscrupulous shopkeeper buys a certain amount of salt at mixes it with white sand so as to earn more profit. The white sand is available free of cost and the two are mixed in equal quantity of weight. Find the percentage profit/loss in selling the adulterated salt if he claims to sell it at 10% loss.a)25% profitb)80% profitc)25% lossd)80% lossCorrect answer is option 'B'. Can you explain this answer?
Question Description
An unscrupulous shopkeeper buys a certain amount of salt at mixes it with white sand so as to earn more profit. The white sand is available free of cost and the two are mixed in equal quantity of weight. Find the percentage profit/loss in selling the adulterated salt if he claims to sell it at 10% loss.a)25% profitb)80% profitc)25% lossd)80% lossCorrect answer is option 'B'. Can you explain this answer? for CAT 2025 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about An unscrupulous shopkeeper buys a certain amount of salt at mixes it with white sand so as to earn more profit. The white sand is available free of cost and the two are mixed in equal quantity of weight. Find the percentage profit/loss in selling the adulterated salt if he claims to sell it at 10% loss.a)25% profitb)80% profitc)25% lossd)80% lossCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An unscrupulous shopkeeper buys a certain amount of salt at mixes it with white sand so as to earn more profit. The white sand is available free of cost and the two are mixed in equal quantity of weight. Find the percentage profit/loss in selling the adulterated salt if he claims to sell it at 10% loss.a)25% profitb)80% profitc)25% lossd)80% lossCorrect answer is option 'B'. Can you explain this answer?.
An unscrupulous shopkeeper buys a certain amount of salt at mixes it with white sand so as to earn more profit. The white sand is available free of cost and the two are mixed in equal quantity of weight. Find the percentage profit/loss in selling the adulterated salt if he claims to sell it at 10% loss.a)25% profitb)80% profitc)25% lossd)80% lossCorrect answer is option 'B'. Can you explain this answer? for CAT 2025 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about An unscrupulous shopkeeper buys a certain amount of salt at mixes it with white sand so as to earn more profit. The white sand is available free of cost and the two are mixed in equal quantity of weight. Find the percentage profit/loss in selling the adulterated salt if he claims to sell it at 10% loss.a)25% profitb)80% profitc)25% lossd)80% lossCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An unscrupulous shopkeeper buys a certain amount of salt at mixes it with white sand so as to earn more profit. The white sand is available free of cost and the two are mixed in equal quantity of weight. Find the percentage profit/loss in selling the adulterated salt if he claims to sell it at 10% loss.a)25% profitb)80% profitc)25% lossd)80% lossCorrect answer is option 'B'. Can you explain this answer?.
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