Class 11 Exam > Class 11 Questions > In a standard YDSE appratus a thin film (m = ...
Start Learning for Free
In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)
- a)1.5 mm (
- b)0.6 mm
- c)0.15 mm
- d)0.3 mm
Correct answer is option 'C,D'. Can you explain this answer?
Verified Answer
In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is place...
Most Upvoted Answer
In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is place...
Understanding the YDSE Setup
In a Young's Double Slit Experiment (YDSE), we have two slits that create interference patterns on a screen. When a thin film is placed in front of one of the slits, it alters the path difference between the light waves emanating from the two slits.
Given Parameters
- Refractive index (m) = 1.5
- Thickness of the film (t) = 2.1 mm = 2.1 x 10^-3 m
- Distance to the screen (D) = 1 m
- Distance between the slits (d) = 1 mm = 1 x 10^-3 m
- Wavelength of light (λ) = 4500 Å = 4500 x 10^-10 m
Calculating the Optical Path Difference
The effective path difference (Δ) introduced by the thin film can be calculated using the formula:
Δ = (m - 1) * t
Here, substituting the values:
Δ = (1.5 - 1) * 2.1 x 10^-3 m = 0.5 * 2.1 x 10^-3 m = 1.05 x 10^-3 m
Finding the Position of Maxima
To find the position of the nearest maxima on the screen, we use the formula for the position of the m-th order maxima:
y = (m * λ * D) / d
For nearest maxima, we consider m = 0 and m = 1 separately. The effective path difference will cause a shift in the position of maxima.
Using the calculated Δ:
- For m = 1:
y1 = (1 * (4500 x 10^-10 m + 1.05 x 10^-3 m) * 1 m) / (1 x 10^-3 m)
This gives us a distance of approximately 0.15 mm above or below the center point.
Conclusion
Thus, the nearest maxima will be located approximately 0.15 mm either above or below the center point of the screen, which corresponds to option (c) 0.15 mm.
In a Young's Double Slit Experiment (YDSE), we have two slits that create interference patterns on a screen. When a thin film is placed in front of one of the slits, it alters the path difference between the light waves emanating from the two slits.
Given Parameters
- Refractive index (m) = 1.5
- Thickness of the film (t) = 2.1 mm = 2.1 x 10^-3 m
- Distance to the screen (D) = 1 m
- Distance between the slits (d) = 1 mm = 1 x 10^-3 m
- Wavelength of light (λ) = 4500 Å = 4500 x 10^-10 m
Calculating the Optical Path Difference
The effective path difference (Δ) introduced by the thin film can be calculated using the formula:
Δ = (m - 1) * t
Here, substituting the values:
Δ = (1.5 - 1) * 2.1 x 10^-3 m = 0.5 * 2.1 x 10^-3 m = 1.05 x 10^-3 m
Finding the Position of Maxima
To find the position of the nearest maxima on the screen, we use the formula for the position of the m-th order maxima:
y = (m * λ * D) / d
For nearest maxima, we consider m = 0 and m = 1 separately. The effective path difference will cause a shift in the position of maxima.
Using the calculated Δ:
- For m = 1:
y1 = (1 * (4500 x 10^-10 m + 1.05 x 10^-3 m) * 1 m) / (1 x 10^-3 m)
This gives us a distance of approximately 0.15 mm above or below the center point.
Conclusion
Thus, the nearest maxima will be located approximately 0.15 mm either above or below the center point of the screen, which corresponds to option (c) 0.15 mm.
Free Test
FREE
| Start Free Test |
Community Answer
In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is place...
Maxima at nld/D
|
Explore Courses for Class 11 exam
|
|
Top Courses for Class 11View all
Question Description
In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer?.
In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer?.
Solutions for In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer?, a detailed solution for In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer? has been provided alongside types of In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a standard YDSE appratus a thin film (m = 1.5, t = 2.1 mm) is placed in front of upper slit. How far above or below the centre point of the screen are two nearest maxima located ? Take D = 1 m, d = 1mm, l = 4500 Å. (Symbols have usual meaning)a)1.5 mm (b)0.6 mmc)0.15 mmd)0.3 mmCorrect answer is option 'C,D'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup