Shopkeeper travelled from his shop straight for 200m. He then turned r...
Solution:
To solve this problem, we will use the Pythagorean theorem to calculate the distance between the shopkeeper's final position and his starting position.
Step 1: Draw a diagram
First, we draw a diagram to represent the shopkeeper's movements. We start with the shopkeeper's initial position (labeled "S") and draw arrows to represent his movements. We label each arrow with the distance the shopkeeper traveled.
```
250m
+-------->
|
|
200m |
|
|
v 200m
-------->
300m
```
Step 2: Calculate the net distance traveled in the x and y directions
Next, we calculate the net distance traveled in the x and y directions. We use the right-hand rule to determine the direction of the x and y axes. We define the positive x direction to be to the right, and the positive y direction to be up.
The shopkeeper traveled 200m to the right, then 250m down, then another 200m to the right, and finally 300m up. Therefore:
- The net distance traveled in the x direction is 200m + 200m = 400m to the right.
- The net distance traveled in the y direction is 250m - 300m = -50m down.
Step 3: Calculate the distance between the starting and ending positions
We can now use the Pythagorean theorem to calculate the distance between the starting and ending positions. The distance (d) is given by:
```
d = sqrt((400m)^2 + (-50m)^2)
= sqrt(160000m^2 + 2500m^2)
= sqrt(162500m^2)
= 403.11m (rounded to two decimal places)
```
Therefore, the shopkeeper is approximately 403.11m from his shop.
Answer: D) none (since the closest option is 500m, which is not the correct answer).
Shopkeeper travelled from his shop straight for 200m. He then turned r...
there is no printing mistake.
if your question format is right .
the answer should be OPTION D (none )
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