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a man is slipping on a frictionless inclined plane and a bag falls down from the same height. then velicity of both is related to(Vb= elocity of bag.,, Vm= velocity of man)...answer is Vb=Vm...how?
Most Upvoted Answer
a man is slipping on a frictionless inclined plane and a bag falls dow...
Explanation:
When a bag falls from a height on a frictionless inclined plane, it will accelerate due to gravity. Similarly, if a man is slipping on the same inclined plane, he will also accelerate due to gravity.
Velocity of Bag:
The velocity of the bag can be calculated using the equation of motion for uniformly accelerated motion:
Vb = u + at
where u is the initial velocity of the bag (which is zero), a is the acceleration due to gravity, and t is the time taken for the bag to fall to the ground.
Since the man and the bag are falling from the same height, they will take the same amount of time to reach the ground. Therefore, the time taken for the bag to fall is equal to the time taken for the man to slide down the inclined plane.
Velocity of Man:
The velocity of the man can also be calculated using the equation of motion for uniformly accelerated motion:
Vm = u + at
where u is the initial velocity of the man (which is zero), a is the acceleration due to gravity, and t is the time taken for the man to slide down the inclined plane.
Since the man and the bag are falling for the same amount of time, they will have the same acceleration due to gravity. Therefore, the velocity of the man will be equal to the velocity of the bag.
Conclusion:
Hence, we can conclude that the velocity of the bag is equal to the velocity of the man, i.e., Vb = Vm.
When a bag falls from a height on a frictionless inclined plane, it will accelerate due to gravity. Similarly, if a man is slipping on the same inclined plane, he will also accelerate due to gravity.
Velocity of Bag:
The velocity of the bag can be calculated using the equation of motion for uniformly accelerated motion:
Vb = u + at
where u is the initial velocity of the bag (which is zero), a is the acceleration due to gravity, and t is the time taken for the bag to fall to the ground.
Since the man and the bag are falling from the same height, they will take the same amount of time to reach the ground. Therefore, the time taken for the bag to fall is equal to the time taken for the man to slide down the inclined plane.
Velocity of Man:
The velocity of the man can also be calculated using the equation of motion for uniformly accelerated motion:
Vm = u + at
where u is the initial velocity of the man (which is zero), a is the acceleration due to gravity, and t is the time taken for the man to slide down the inclined plane.
Since the man and the bag are falling for the same amount of time, they will have the same acceleration due to gravity. Therefore, the velocity of the man will be equal to the velocity of the bag.
Conclusion:
Hence, we can conclude that the velocity of the bag is equal to the velocity of the man, i.e., Vb = Vm.
Community Answer
a man is slipping on a frictionless inclined plane and a bag falls dow...
On a friction less inclined plane only gravitational force acts also in the case of freely falling body and God independent of the mass
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a man is slipping on a frictionless inclined plane and a bag falls down from the same height. then velicity of both is related to(Vb= elocity of bag.,, Vm= velocity of man)...answer is Vb=Vm...how?
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