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The length of the arc of the semi cubical parabola y2 = x3 from its vertex to the point (1, 1) i s ______ . (correct upto two decimal places)
    Correct answer is '1.44'. Can you explain this answer?
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    Explanation:

    The arc length of the curve can be found using the formula for arc length of a curve:

    Arc Length = ∫ [sqrt(1 + (dy/dx)²)] dx

    In this case, the curve is represented by the equation y² = x³.

    1. Find dy/dx:
    Differentiating y² = x³ with respect to x, we get:
    2y(dy/dx) = 3x²
    dy/dx = (3x²)/(2y)

    2. Find the integral:
    Substitute dy/dx into the arc length formula:
    Arc Length = ∫ [sqrt(1 + (3x²/2y)²)] dx
    Simplify the integrand:
    = ∫ [sqrt(1 + (9x⁴)/(4y²))] dx
    = ∫ [sqrt(1 + (9x⁴)/(4x³))] dx
    = ∫ [sqrt(1 + (9x)/(4))] dx

    3. Limits of integration:
    To find the arc length from the vertex to the point (1, 1), we need to find the value of x when y = 1:
    1² = x³
    x = 1

    4. Calculate the arc length:
    Now, plug in the limits of integration:
    Arc Length = ∫ [sqrt(1 + (9x)/(4))] dx, from x=0 to x=1
    = ∫ [sqrt(1 + (9x)/(4))] dx, from 0 to 1
    = ∫ [sqrt(1 + (9x)/(4))] dx, from 0 to 1
    ≈ 1.44 (rounded to two decimal places)

    Therefore, the length of the arc of the semi-cubical parabola from its vertex to the point (1, 1) is approximately 1.44 units.
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    The length of the arc of the semi cubical parabola y2 = x3 from its vertex to the point (1, 1) i s ______ . (correct upto two decimal places)Correct answer is '1.44'. Can you explain this answer?
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