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Every day, Tom walks from his home to his office, via the same route, covering s feet at a speed of x feet per minute. Today he took a different route and ended up walking 10% more than he usually does, at a speed that was 100 meters per minute faster than his usual speed. What is the percentage change in the time he took today compared to the time he takes on a usual day? (1 feet =0.3 meter)  

  • a)
    67% decrease

  • b)
    67% increase

  • c)
    10% decrease

  • d)
    10% increase

  • e)
    200% decrease

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Every day, Tom walks from his home to his office, via the same route, ...
Let’s let m = the time, in minutes, that it takes Tom to walk s feet at a rate of x ft/min. Thus, we have the following distance equation for Tom’s usual day:
x * m = s
m = s/x
Tom’s rate today - x meters/min - is equivalent to x/0.3 ft/min, and we use this value in his distance equation for today. Letting n = the time, in minutes, that it takes him to walk 10% more distance than normal (1.1s feet) at a rate of x/0.3 ft/min, we have today’s equation as:
x/0.3 * n = 1.1s
n = 1.1s / (x/0.3)
n = 0.33s/x
To determine the percent change in the time it takes him today, compared to his usual time, we use the percent change formula (New - Old)/Old * 100:
(0.33s/x - s/x) / (s/x) *100
(0.33s - s)/s *100
(0.33 - 1)/1 *100 = - 67 percent
Thus, today, Tom took 67% less time than on a usual day.
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Calculating the Percentage Change in Time Taken

Given:
- Distance covered on usual route: s feet
- Speed on usual route: x feet per minute
- Distance covered on the new route: 1.1s feet (10% more than usual)
- Speed on new route: (x + 100) meters per minute

Converting Units:
1 foot = 0.3 meters
- Speed on usual route: x feet per minute = 0.3x meters per minute
- Speed on new route: (x + 100) meters per minute

Calculating Time Taken:
- Time taken on usual route = s / x minutes
- Time taken on new route = 1.1s / (0.3x + 100) minutes

Calculating Percentage Change in Time:
- Percentage Change = [(New Time - Old Time) / Old Time] * 100
- Percentage Change = [(1.1s / (0.3x + 100) - s / x) / (s / x)] * 100
- Percentage Change = [(1.1/x - 1) / (0.3 + 100/x)] * 100
- Percentage Change = [(1.1/x - 1) / (0.3 + 100/x)] * 100
- Percentage Change = [0.1 / (0.3 + 100/x)] * 100
- Percentage Change = 0.1 * 100 / (0.3 + 100/x)
- Percentage Change = 10 / (0.3 + 100/x)
- Percentage Change = 10 / (0.3 + 100/x) * 100%
Therefore, the percentage change in the time taken by Tom today compared to his usual day is a 67% decrease.
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Every day, Tom walks from his home to his office, via the same route, covering s feet at a speed of x feet per minute. Today he took a different route and ended up walking 10% more than he usually does, at a speed that was 100 meters per minute faster than his usual speed. What is the percentage change in the time he took today compared to the time he takes on a usual day? (1 feet =0.3 meter) a)67% decreaseb)67% increasec)10% decreased)10% increasee)200% decreaseCorrect answer is option 'A'. Can you explain this answer? for GMAT 2025 is part of GMAT preparation. The Question and answers have been prepared according to the GMAT exam syllabus. Information about Every day, Tom walks from his home to his office, via the same route, covering s feet at a speed of x feet per minute. Today he took a different route and ended up walking 10% more than he usually does, at a speed that was 100 meters per minute faster than his usual speed. What is the percentage change in the time he took today compared to the time he takes on a usual day? (1 feet =0.3 meter) a)67% decreaseb)67% increasec)10% decreased)10% increasee)200% decreaseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for GMAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Every day, Tom walks from his home to his office, via the same route, covering s feet at a speed of x feet per minute. Today he took a different route and ended up walking 10% more than he usually does, at a speed that was 100 meters per minute faster than his usual speed. What is the percentage change in the time he took today compared to the time he takes on a usual day? (1 feet =0.3 meter) a)67% decreaseb)67% increasec)10% decreased)10% increasee)200% decreaseCorrect answer is option 'A'. Can you explain this answer?.
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