Class 12 Exam > Class 12 Questions > A capacitor C1 = 4mF is connected in series w...
Start Learning for Free
A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 is
- a)1 : 4
- b)4 : 1
- c)1 : 2
- d)2 : 1
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A capacitor C1 = 4mF is connected in series with another capacitor C2 ...
Voltage in series connections are,
V1=C2/{(C1+C2) x V} V2={C1/(C1+C2)xV}]
V1=(1/S) x 200
V2=(4/S) x200
Ration, V1/V2=((1/S) x200)/((4/S)x200)=1:4
V1=C2/{(C1+C2) x V} V2={C1/(C1+C2)xV}]
V1=(1/S) x 200
V2=(4/S) x200
Ration, V1/V2=((1/S) x200)/((4/S)x200)=1:4
Most Upvoted Answer
A capacitor C1 = 4mF is connected in series with another capacitor C2 ...
**Solution:**
When two capacitors are connected in series, the charge on both the capacitors is the same. The potential drop across each capacitor depends on its capacitance.
Let us denote the potential drop across C1 by V1 and the potential drop across C2 by V2.
**Applying Kirchhoff's Voltage Law**
The total potential difference across the combination of capacitors is equal to the sum of potential differences across each capacitor.
V = V1 + V2
V = Q/C1 + Q/C2
V = Q(1/C1 + 1/C2)
Q = CV
Q = (C1C2/(C1 + C2)) V
Q = 4 × 1/(4 + 1) × 200 = 160 V
**Calculating the Potential Drop Across Each Capacitor**
The potential drop across C1 is given by
V1 = Q/C1
V1 = (160/4) V = 40 V
The potential drop across C2 is given by
V2 = Q/C2
V2 = (160/1) V = 160 V
**Ratio of Potential Drop Across C1 and C2**
The ratio of potential drop across C1 and C2 is
V1 : V2 = 40 : 160
V1 : V2 = 1 : 4
Hence, the correct option is (a) 1:4.
When two capacitors are connected in series, the charge on both the capacitors is the same. The potential drop across each capacitor depends on its capacitance.
Let us denote the potential drop across C1 by V1 and the potential drop across C2 by V2.
**Applying Kirchhoff's Voltage Law**
The total potential difference across the combination of capacitors is equal to the sum of potential differences across each capacitor.
V = V1 + V2
V = Q/C1 + Q/C2
V = Q(1/C1 + 1/C2)
Q = CV
Q = (C1C2/(C1 + C2)) V
Q = 4 × 1/(4 + 1) × 200 = 160 V
**Calculating the Potential Drop Across Each Capacitor**
The potential drop across C1 is given by
V1 = Q/C1
V1 = (160/4) V = 40 V
The potential drop across C2 is given by
V2 = Q/C2
V2 = (160/1) V = 160 V
**Ratio of Potential Drop Across C1 and C2**
The ratio of potential drop across C1 and C2 is
V1 : V2 = 40 : 160
V1 : V2 = 1 : 4
Hence, the correct option is (a) 1:4.
Free Test
FREE
| Start Free Test |
Community Answer
A capacitor C1 = 4mF is connected in series with another capacitor C2 ...
|
Explore Courses for Class 12 exam
|
|
Top Courses for Class 12View all
Question Description
A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer?.
A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer?.
Solutions for A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A capacitor C1 = 4mF is connected in series with another capacitor C2 = 1mF. The combination is connected across a d.c. source of voltage 200V. The ratio of potential across C1 and C2 isa)1 : 4b)4 : 1c)1 : 2d)2 : 1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup