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If variance of first n natural numbers is 10 and variance of first m even natural numbers is 16 then the value of m + n is
    Correct answer is '18'. Can you explain this answer?
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    If variance of first n natural numbers is 10 and variance of first m e...

    ⇒ n2 - 1 = 120
    ⇒ n = 11
    Var (2, 4, 6,.....,2m) = 16
    ⇒ var (1, 2,....,m) = 4
    ⇒ m2 - 1 = 48
    ⇒ m = 7
    ⇒ m + n = 18 
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    Most Upvoted Answer
    If variance of first n natural numbers is 10 and variance of first m e...
    Given:
    Variance of first n natural numbers = 10
    Variance of first m even natural numbers = 16

    To find:
    The value of m and n

    Solution:
    Let's start by understanding what variance means in statistics.

    Variance:
    Variance is a measure of how spread out the numbers in a dataset are. It quantifies the dispersion of a set of values. Mathematically, variance is the average of the squared differences from the mean.

    Formula for Variance:
    The formula for variance is given by:
    Variance = (sum of (x - mean)^2) / n

    where x is a data point, mean is the average of the data points, and n is the total number of data points.

    Variance of first n natural numbers:
    To find the variance of the first n natural numbers, we need to determine the sum of the squares of these numbers.

    The sum of the squares of the first n natural numbers can be calculated using the formula for the sum of squares:
    Sum of Squares = n * (n + 1) * (2n + 1) / 6

    Using this formula, we can calculate the sum of squares for the first n natural numbers and substitute it into the variance formula.

    Variance of first m even natural numbers:
    Similarly, we can find the sum of squares of the first m even natural numbers and substitute it into the variance formula.

    Equating the variances:
    Since the variance of the first n natural numbers is given as 10 and the variance of the first m even natural numbers is given as 16, we can equate the two variances to find a relationship between n and m.

    (sum of squares of the first n natural numbers) / n = 10
    (sum of squares of the first m even natural numbers) / m = 16

    Simplifying the equations:
    By simplifying the equations, we get:
    Sum of squares of the first n natural numbers = 10n
    Sum of squares of the first m even natural numbers = 16m

    Using the formulas for the sum of squares:
    We can substitute the formulas for the sum of squares into the equations:
    n * (n + 1) * (2n + 1) / 6 = 10n
    m * (m + 1) * (2m + 1) / 6 = 16m

    Solving the equations:
    We can simplify the equations and solve for n and m:
    n^3 + n^2 - 60n = 0
    m^3 + m^2 - 48m = 0

    By observing the equations, we can find that n = 10 satisfies the first equation, and m = 8 satisfies the second equation.

    Therefore, the value of m * n = 8 * 10 = 80.

    Conclusion:
    The value of m * n is 80, which is not equal to 18. Therefore, the given answer of 18 is incorrect.
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    If variance of first n natural numbers is 10 and variance of first m even natural numbers is 16 then the value of m + n isCorrect answer is '18'. Can you explain this answer?
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    If variance of first n natural numbers is 10 and variance of first m even natural numbers is 16 then the value of m + n isCorrect answer is '18'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If variance of first n natural numbers is 10 and variance of first m even natural numbers is 16 then the value of m + n isCorrect answer is '18'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If variance of first n natural numbers is 10 and variance of first m even natural numbers is 16 then the value of m + n isCorrect answer is '18'. Can you explain this answer?.
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