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An ideal gas at initial temperature 300 K is compressed adiabatically of its initial volume. The gas is then expanded isobarically to double its volume. Then final temperature of gas round to nearest integer is:
 
    Correct answer is '1819'. Can you explain this answer?
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    An ideal gas at initial temperature 300 K is compressed adiabaticallyo...
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    An ideal gas at initial temperature 300 K is compressed adiabaticallyo...

    PVy = constant
    TVy–1 = constant 

    TB = 300 × 28/5
    Now for BC process


    Tc = 1819 K
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    An ideal gas at initial temperature 300 K is compressed adiabaticallyof its initialvolume. The gas is then expanded isobarically to double its volume. Then final temperature of gasround to nearest integer is:Correct answer is '1819'. Can you explain this answer?
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    An ideal gas at initial temperature 300 K is compressed adiabaticallyof its initialvolume. The gas is then expanded isobarically to double its volume. Then final temperature of gasround to nearest integer is:Correct answer is '1819'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An ideal gas at initial temperature 300 K is compressed adiabaticallyof its initialvolume. The gas is then expanded isobarically to double its volume. Then final temperature of gasround to nearest integer is:Correct answer is '1819'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ideal gas at initial temperature 300 K is compressed adiabaticallyof its initialvolume. The gas is then expanded isobarically to double its volume. Then final temperature of gasround to nearest integer is:Correct answer is '1819'. Can you explain this answer?.
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