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The polynomial function f(x) of degree 6 ,which satisfies,
and has local maxima at x =1 and local minimum at x = 0 and x =2, is
  • a)
    x4 - x5 + x6
  • b)
  • c)
  • d)
    x4 + x5 + x6
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The polynomial function f(x) of degree 6 ,which satisfies,and has loca...
The limit can only exist if f(x) is having least degree as that of 4.
Given that f(x) has local extremum at x = 0,1,2
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Most Upvoted Answer
The polynomial function f(x) of degree 6 ,which satisfies,and has loca...
The limit can only exist if f(x) is having least degree as that of 4.
Given that f(x) has local extremum at x = 0,1,2
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Community Answer
The polynomial function f(x) of degree 6 ,which satisfies,and has loca...
The limit can only exist if f(x) is having least degree as that of 4.
Given that f(x) has local extremum at x = 0,1,2
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The polynomial function f(x) of degree 6 ,which satisfies,and has local maxima at x =1 and local minimum at x = 0 and x =2, isa)x4 - x5 + x6b)c)d)x4 + x5 + x6Correct answer is option 'B'. Can you explain this answer?
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The polynomial function f(x) of degree 6 ,which satisfies,and has local maxima at x =1 and local minimum at x = 0 and x =2, isa)x4 - x5 + x6b)c)d)x4 + x5 + x6Correct answer is option 'B'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about The polynomial function f(x) of degree 6 ,which satisfies,and has local maxima at x =1 and local minimum at x = 0 and x =2, isa)x4 - x5 + x6b)c)d)x4 + x5 + x6Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The polynomial function f(x) of degree 6 ,which satisfies,and has local maxima at x =1 and local minimum at x = 0 and x =2, isa)x4 - x5 + x6b)c)d)x4 + x5 + x6Correct answer is option 'B'. Can you explain this answer?.
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