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Saatwik drives his car from his house to the station and picks up Seema from there every day at 7.00 p.m. and then they go to the coffeehouse. The coffeehouse is between Saatwik’s house and the station, on the road joining these two places. One day, she reached the station at 6.00 p.m. and instead of waiting for him at the station, she started walking at a speed of 10 km/hr. Saatwik left his house at the usual time and picked her up on his way to the station. If they reached the coffeehouse 20 minutes earlier than usual, what is the speed of Saatwik’s car? (in km/hr)
Correct answer is '50'. Can you explain this answer?
Verified Answer
Saatwik drives his car from his house to the station and picks up Seem...
Let the speed of Saatwik’s car be x km/hr.
As they reached 20 minutes earlier than usual, Saatwik must have travelled 10 minutes lesser in both the directions. This means that he must have picked her up at 6.50 p.m.
The distance covered by Seema in 50 minutes would be covered by Saatwik in 10 minutes.
Speed is inversely proportional to time when the distance is constant.

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Saatwik drives his car from his house to the station and picks up Seem...
Given information:
- Saatwik drives his car from his house to the station and picks up Seema from there every day at 7.00 p.m.
- The coffeehouse is located between Saatwik's house and the station, on the road joining these two places.
- One day, Seema reached the station at 6.00 p.m. and started walking towards the coffeehouse at a speed of 10 km/hr.
- Saatwik left his house at the usual time and picked her up on his way to the station.
- They reached the coffeehouse 20 minutes earlier than usual.

Objective:
Find the speed of Saatwik's car.

Assumptions:
1. The distance between Saatwik's house and the station is the same as the distance between the station and the coffeehouse.
2. Saatwik and Seema always travel at a constant speed.

Approach:
1. Let's assume the distance between Saatwik's house and the station (and also between the station and the coffeehouse) is 'd' km.
2. Seema starts walking from the station at 6.00 p.m., one hour before the usual pickup time.
3. In this one hour, Seema covers a distance of 10 km (since her speed is 10 km/hr).
4. When Saatwik starts driving from his house at 7.00 p.m., Seema has already covered 10 km towards the coffeehouse.
5. Let 't' be the time taken by Saatwik to cover the remaining distance from his house to the station.
6. Since Saatwik and Seema both reach the coffeehouse 20 minutes earlier than usual, their total travel time is 40 minutes less than usual.
7. The usual travel time from Saatwik's house to the station is 't' hours.
8. The usual travel time from the station to the coffeehouse is 'd - t' hours.
9. The total usual travel time is 't + (d - t)' hours, which is equal to 'd' hours.
10. The total travel time in this case is 'd - 40/60' hours.
11. Using the formula Distance = Speed × Time, we can write the equation: d = Saatwik's speed × t + Seema's speed × (d - t).
12. Substituting the values, we get: d = Saatwik's speed × t + 10 × (d - t).

Solution:
1. Simplifying the equation, we get: d = Saatwik's speed × t + 10d - 10t.
2. Rearranging the terms, we get: 9d = Saatwik's speed × t + 9t.
3. Dividing both sides by 9, we get: d = (Saatwik's speed/9) × t + t.
4. Since d = t + 10, we can rewrite the equation as: t + 10 = (Saatwik's speed/9) × t + t.
5. Simplifying the equation, we get: 10 = (Saatwik's speed/9) × t.
6. Dividing both sides by t, we get: 10/t = Sa
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Saatwik drives his car from his house to the station and picks up Seema from there every day at 7.00 p.m. and then they go to the coffeehouse. The coffeehouse is between Saatwiks house and the station, on the road joining these two places. One day, she reached the station at 6.00 p.m. and instead of waiting for him at the station, she started walking at a speed of 10 km/hr. Saatwik left his house at the usual time and picked her up on his way to the station. If they reached the coffeehouse 20 minutes earlier than usual, what is the speed of Saatwiks car? (in km/hr)Correct answer is '50'. Can you explain this answer?
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