Meera went to a park 150 m long and 80 m wide. She took one complete r...

Let ABCD is a park whose lengths are BC, AD and widths are AB, CD, respectively. Hence, AB = CD = 80 m. and BC = DA = 150m Now, the sum of the lengths of four sides
=AB + BC + CD + DA
= 80 m + 150 m + 80 m + 150 m
= (80 + 150 + 80 + 150) m
=460 m
Perimeter of the park = sum of the lengths of four sides of the park = 460 m
Hence, distance covered by Meera is 460 m.
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Meera went to a park 150 m long and 80 m wide. She took one complete r...
To find the distance covered by Meera when she took one complete round on the boundary of the park, we need to add the distances travelled along the length and the width of the park.
Length of the park: 150 m
Width of the park: 80 m
Distance travelled along the length:
When Meera starts at one end of the park and walks along the length, she covers a distance equal to the length of the park. So, the distance travelled along the length is 150 m.
Distance travelled along the width:
Once Meera reaches the other end of the park, she takes a right turn and walks along the width. This distance is equal to the width of the park. So, the distance travelled along the width is 80 m.
Total distance covered:
To find the total distance covered, we add the distance travelled along the length and the width:
Total distance = Distance along the length + Distance along the width
Total distance = 150 m + 80 m
Total distance = 230 m
Therefore, the correct answer is option (A) 230 m.