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The power incident on a detector of light is 100 nW. Determine the number of photons per second incident on the detector if the wavelength is 800 nm.
  • a)
    4 x 1011 photons /s
  • b)
    2 x 1011 photons /s
  • c)
    4 x 1010 photons /s
  • d)
    1 x 1011photons /s
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The power incident on a detector of light is 100 nW. Determine the num...
Energy incident per sec = Number of incident photon per sec x 
Or 
h = 6.62 x 10-34 J.s c = 
∴ N = 4 x 1011 photons per sec.
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Most Upvoted Answer
The power incident on a detector of light is 100 nW. Determine the num...
Given:
Power incident on the detector = 100 nW
Wavelength of light = 800 nm

To find:
Number of photons per second incident on the detector

Formula:
The power of light can be calculated using the formula:
Power = Energy / Time

The energy of a single photon can be calculated using the formula:
Energy = Planck's constant * Speed of light / Wavelength

The number of photons can be calculated using the formula:
Number of photons = Power / Energy

Calculation:
1. Convert the power incident on the detector from nanowatts to watts:
Power (in W) = 100 nW = 100 × 10^(-9) W

2. Calculate the energy of a single photon:
Energy = (Planck's constant * Speed of light) / Wavelength
= (6.63 × 10^(-34) Js * 3 × 10^8 m/s) / (800 × 10^(-9) m)
= (1.989 × 10^(-25) J)

3. Calculate the number of photons incident on the detector per second:
Number of photons = Power / Energy
= (100 × 10^(-9) W) / (1.989 × 10^(-25) J)
= (5.03 × 10^15 photons/s)

Answer:
The number of photons per second incident on the detector is approximately 5.03 × 10^15, which is closest to option 'A': 4 × 10^11 photons/s.
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Community Answer
The power incident on a detector of light is 100 nW. Determine the num...
Energy incident per sec = Number of incident photon per sec x 
Or 
h = 6.62 x 10-34 J.s c = 
∴ N = 4 x 1011 photons per sec.
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