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There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is [2010]
  • a)
    36
  • b)
    66
  • c)
    108
  • d)
    3
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
There are two urns. Urn A has 3 distinct red balls and urn B has 9 dis...
Total number of ways = 3C2 x 9C2
 = 3 x 36 = 108
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Most Upvoted Answer
There are two urns. Urn A has 3 distinct red balls and urn B has 9 dis...
Analysis:
To find the number of ways in which the balls can be transferred from one urn to another, we can break down the process into steps and calculate the possibilities at each step.

Step 1: Choose 2 balls from urn A
Since urn A has 3 red balls, the number of ways to choose 2 balls from urn A is 3C2 = 3.

Step 2: Choose 2 balls from urn B
Since urn B has 9 blue balls, the number of ways to choose 2 balls from urn B is 9C2 = 36.

Total number of ways:
The total number of ways to transfer the balls is the product of the number of ways in Step 1 and Step 2:
Total ways = 3 * 36 = 108.
Therefore, the correct answer is option C) 108.
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