Divisibility Test for 5:

The divisibility test for 5 is a rule that helps us determine whether a given number is divisible by 5 or not. According to this test, if the last digit of a number is either 0 or 5, then the number is divisible by 5. Let's understand this rule in detail.

Explanation:

To understand the divisibility test for 5, let's consider a number, say 135. The last digit of this number is 5, so we can say that 135 is divisible by 5. But why?

Reasoning:

When we write a number, each digit represents a specific place value. The rightmost digit is known as the units place, the next digit to the left is the tens place, the next digit to the left is the hundreds place, and so on.

In our example, the number 135 has the digit 5 in the units place. This digit represents the value of 5 multiplied by 1 (since it is in the units place). So, the value contributed by the units place is 5.

Key Point:

Now, we know that any number multiplied by 5 ends in either 0 or 5. So, when the units place digit is 5, the entire number will end in 5.

Application of the Divisibility Test:

To apply the divisibility test for 5, we simply need to check the units place digit of the given number. If it is either 0 or 5, then the number is divisible by 5.

For example:
- 45 is divisible by 5 because the units place digit is 5.
- 120 is divisible by 5 because the units place digit is 0.

Exceptions:

There are no exceptions to this rule. If the units place digit is not 0 or 5, then the number is not divisible by 5.

Summary:

To summarize, the divisibility test for 5 states that if the units place digit of a number is either 0 or 5, then the number is divisible by 5. This rule is based on the fact that any number multiplied by 5 ends in either 0 or 5. By applying this test, we can quickly determine whether a given number is divisible by 5 or not.

The answer is both 0 and 5 because divisibility by 5 is only possible when the last digit of a number is 0 or 5.