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how many digits 3 digit numbers can be formed by using the digit 2 0 5 without repeating any digit in the number please give me answer fast
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how many digits 3 digit numbers can be formed by using the digit 2 0 5...
To find the number of 3-digit numbers that can be formed using the digits 2, 0, and 5 without repeating any digit, we can use the concept of permutations.

Permutations are arrangements of objects in a specific order. In this case, we want to find the number of arrangements of the digits 2, 0, and 5 to form 3-digit numbers without repetition.

Step 1: Determine the number of choices for the first digit.
Since we cannot repeat any digit, we have 3 choices for the first digit.

Step 2: Determine the number of choices for the second digit.
After selecting the first digit, we have 2 remaining digits to choose from for the second digit.

Step 3: Determine the number of choices for the third digit.
After selecting the first and second digits, we are left with only 1 digit for the third digit.

Step 4: Multiply the number of choices for each step.
To find the total number of 3-digit numbers, we need to multiply the number of choices for each step.

Number of choices for the first digit = 3
Number of choices for the second digit = 2
Number of choices for the third digit = 1

Total number of 3-digit numbers = 3 x 2 x 1 = 6

Therefore, there are 6 different 3-digit numbers that can be formed using the digits 2, 0, and 5 without repeating any digit.
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how many digits 3 digit numbers can be formed by using the digit 2 0 5 without repeating any digit in the number please give me answer fast Related: NCERT Solution - Knowing Your Number?
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