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If α and β (α < β) are the roots of the equation x2 + bx + c = 0, where c < 0 < β, then (2000S)
  • a)
    0 < α < β
  • b)
    α < 0 < β < | α |
  • c)
    α < β < 0
  • d)
    α < 0 < | α | < β
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If α and β (α < β) are the roots of the equat...
Given c < 0 < b   and α + β = – b ....(1) αβ = c
....(2)
From (2), c < 0 ⇒ αβ < 0 ⇒ either a is  -ve or β is - ve and second ;quantity is positive.
from (1), b > 0 ⇒ – b < 0  ⇒ α + β < 0 ⇒ the sum is negative
⇒ modules of nengative quantity is > modulus of positive quantity but α< β is given.
Therefore, it is clear that α is negative and β is positive and modulus of α is greater than modulus of β ⇒ α< 0 <β< |α|
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If α and β (α < β) are the roots of the equation x2 + bx + c = 0, where c < 0 < β, then (2000S)a)0 < α < βb)α < 0 < β < |α |c)α < β < 0d)α < 0 < | α| < βCorrect answer is option 'B'. Can you explain this answer?
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If α and β (α < β) are the roots of the equation x2 + bx + c = 0, where c < 0 < β, then (2000S)a)0 < α < βb)α < 0 < β < |α |c)α < β < 0d)α < 0 < | α| < βCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If α and β (α < β) are the roots of the equation x2 + bx + c = 0, where c < 0 < β, then (2000S)a)0 < α < βb)α < 0 < β < |α |c)α < β < 0d)α < 0 < | α| < βCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If α and β (α < β) are the roots of the equation x2 + bx + c = 0, where c < 0 < β, then (2000S)a)0 < α < βb)α < 0 < β < |α |c)α < β < 0d)α < 0 < | α| < βCorrect answer is option 'B'. Can you explain this answer?.
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