The intensity of light transmitted by the analyzer is maximum whena)Th...
From malu's law,
If I0 is intensity of plane polarised light incident on an analyser and (thete) is the angle between axes of polariser and analyser, then intensity of polarised light transmitted from analyser ,I = I0 cos(^2) thete,
ie, when (thete)=0, cos(^2) 0=1, then I= I0
ie, the transmission axes of polariser and analyser are paralell.
The intensity of light transmitted by the analyzer is maximum whena)Th...
The Concept of Polarization
Polarization is a phenomenon where light waves oscillate in particular directions. A polarizer allows light waves of a specific orientation to pass through while blocking others.
Understanding Polarizers and Analyzers
- Polarizer: A device that converts unpolarized light into polarized light by allowing only light waves of a certain orientation to pass through.
- Analyzer: A second polarizing filter that is used to analyze the polarized light transmitted by the polarizer.
Condition for Maximum Intensity
The intensity of light transmitted by the analyzer is maximized under specific conditions:
- Parallel Orientation: The transmission axes of the analyzer and the polarizer must be aligned parallel to each other. This means both filters allow the same orientation of light waves to pass through.
Explanation of Option C
- When the transmission axes are parallel, the light waves that have passed through the polarizer are allowed to pass through the analyzer without any obstruction.
- This alignment results in maximum transmission of light, leading to maximum intensity observed at the output.
Why Other Options are Incorrect
- Option A: Perpendicular axes block all light, resulting in zero intensity.
- Option B: Fully polarized light does not relate to the orientation of the analyzer.
- Option D: Partially polarized light does not achieve maximum intensity unless aligned correctly.
Conclusion
In summary, the maximum intensity of light transmitted by the analyzer occurs when its transmission axis is parallel to that of the polarizer, confirming that option 'C' is indeed the correct answer.