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The sum of the first 20 term of a GP is 244 times the sum of its first 10term the common ratio is?
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Problem: The sum of the first 20 terms of a GP is 244 times the sum of its first 10 terms. Find the common ratio.

Solution:

Let the first term of the GP be 'a' and the common ratio be 'r'.

We know that the sum of the first 'n' terms of a GP is given by:

Sₙ = a(1 - rⁿ)/(1 - r)

Using this formula, we can find the sum of the first 20 terms and the sum of the first 10 terms:

S₂₀ = a(1 - r²⁰)/(1 - r)

S₁₀ = a(1 - r¹⁰)/(1 - r)

We are given that:

S₂₀ = 244S₁₀

Substituting the values of S₂₀ and S₁₀, we get:

a(1 - r²⁰)/(1 - r) = 244a(1 - r¹⁰)/(1 - r)

Cancelling out the common factor of 'a' from both sides, we get:

(1 - r²⁰)/(1 - r) = 244(1 - r¹⁰)/(1 - r)

Expanding the brackets and simplifying the equation, we get:

r¹⁰ = 1/244

Taking the 10th root of both sides, we get:

r = 1/2.44

Therefore, the common ratio is 0.4098 (approx).

Answer: The common ratio is 0.4098.
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