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A sample bituminous coal get the following ultimate analysis by mass c:81.9% H: 4.9% O2: 6% N2: 2.3% ash : 4.9% calulate volumetric analysis of wet and dry products when air supplied is 25% in excess of that complete combustion?
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Volumetric Analysis of Wet and Dry Products from Bituminous Coal Combustion
Ultimate Analysis of Bituminous Coal
- Carbon (C): 81.9%
- Hydrogen (H): 4.9%
- Oxygen (O2): 6%
- Nitrogen (N2): 2.3%
- Ash: 4.9%
Calculation of Air Required for Complete Combustion
- Calculate the stoichiometric air required for complete combustion using the ultimate analysis and assumption of all nitrogen in air.
- C + O2 → CO2 + N2
- H + 0.5O2 → H2O
- O2 + N2 → 79%N2 + 21%O2
- The stoichiometric air required is 11.59 kg per kg of fuel.
- The excess air supplied is 25% of the stoichiometric air, which is 2.9 kg per kg of fuel.
Calculation of Dry Volumetric Analysis of Products
- Calculate the volume of dry products using the ideal gas law and assuming the products are at standard temperature and pressure (STP).
- CO2: 81.9% × (1−0.049) × 44 g/mol / 12 g/mol = 2.73 m3 per kg of fuel
- H2O: 4.9% × 18 g/mol / 2 g/mol = 0.44 m3 per kg of fuel
- N2: 2.3% × 79% × 28 g/mol / 28 g/mol = 0.42 m3 per kg of fuel
- O2: 21% × 2.9 kg per kg of fuel × 1000 g/kg / 32 g/mol = 1.93 m3 per kg of fuel
- Total volume of dry products = 5.52 m3 per kg of fuel
Calculation of Wet Volumetric Analysis of Products
- Calculate the volume of wet products by multiplying the volume of dry products by the ratio of wet to dry gas volumes at STP.
- CO2: 1.3
- H2O: 1
- N2: 1
- O2: 1.1
- Total volume of wet products = 6.07 m3 per kg of fuel
Ultimate Analysis of Bituminous Coal
- Carbon (C): 81.9%
- Hydrogen (H): 4.9%
- Oxygen (O2): 6%
- Nitrogen (N2): 2.3%
- Ash: 4.9%
Calculation of Air Required for Complete Combustion
- Calculate the stoichiometric air required for complete combustion using the ultimate analysis and assumption of all nitrogen in air.
- C + O2 → CO2 + N2
- H + 0.5O2 → H2O
- O2 + N2 → 79%N2 + 21%O2
- The stoichiometric air required is 11.59 kg per kg of fuel.
- The excess air supplied is 25% of the stoichiometric air, which is 2.9 kg per kg of fuel.
Calculation of Dry Volumetric Analysis of Products
- Calculate the volume of dry products using the ideal gas law and assuming the products are at standard temperature and pressure (STP).
- CO2: 81.9% × (1−0.049) × 44 g/mol / 12 g/mol = 2.73 m3 per kg of fuel
- H2O: 4.9% × 18 g/mol / 2 g/mol = 0.44 m3 per kg of fuel
- N2: 2.3% × 79% × 28 g/mol / 28 g/mol = 0.42 m3 per kg of fuel
- O2: 21% × 2.9 kg per kg of fuel × 1000 g/kg / 32 g/mol = 1.93 m3 per kg of fuel
- Total volume of dry products = 5.52 m3 per kg of fuel
Calculation of Wet Volumetric Analysis of Products
- Calculate the volume of wet products by multiplying the volume of dry products by the ratio of wet to dry gas volumes at STP.
- CO2: 1.3
- H2O: 1
- N2: 1
- O2: 1.1
- Total volume of wet products = 6.07 m3 per kg of fuel
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A sample bituminous coal get the following ultimate analysis by mass c:81.9% H: 4.9% O2: 6% N2: 2.3% ash : 4.9% calulate volumetric analysis of wet and dry products when air supplied is 25% in excess of that complete combustion?
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A sample bituminous coal get the following ultimate analysis by mass c:81.9% H: 4.9% O2: 6% N2: 2.3% ash : 4.9% calulate volumetric analysis of wet and dry products when air supplied is 25% in excess of that complete combustion? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A sample bituminous coal get the following ultimate analysis by mass c:81.9% H: 4.9% O2: 6% N2: 2.3% ash : 4.9% calulate volumetric analysis of wet and dry products when air supplied is 25% in excess of that complete combustion? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample bituminous coal get the following ultimate analysis by mass c:81.9% H: 4.9% O2: 6% N2: 2.3% ash : 4.9% calulate volumetric analysis of wet and dry products when air supplied is 25% in excess of that complete combustion?.
A sample bituminous coal get the following ultimate analysis by mass c:81.9% H: 4.9% O2: 6% N2: 2.3% ash : 4.9% calulate volumetric analysis of wet and dry products when air supplied is 25% in excess of that complete combustion? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A sample bituminous coal get the following ultimate analysis by mass c:81.9% H: 4.9% O2: 6% N2: 2.3% ash : 4.9% calulate volumetric analysis of wet and dry products when air supplied is 25% in excess of that complete combustion? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample bituminous coal get the following ultimate analysis by mass c:81.9% H: 4.9% O2: 6% N2: 2.3% ash : 4.9% calulate volumetric analysis of wet and dry products when air supplied is 25% in excess of that complete combustion?.
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