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Volumetric analysis of sample of dry products -of combustion gave the following results: CO2 = 10% CO = 1% O2 = 8% N2 = 81%
Their proportions by weight will be
- a)440: 28 : 256 : 2268
- b)22 : 14 : 256 : 1134
- c)440: 14: 28: 2268
- d)22: 28: 14: 1134
Correct answer is option 'A'. Can you explain this answer?
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Volumetric analysis of sample of dry products -of combustion gave the ...
Conversion from volumetric to gravimetric is done as below:
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Volumetric analysis of sample of dry products -of combustion gave the ...
Proportions by Weight in Volumetric Analysis of Dry Products
Given:
CO2 = 10%
CO = 1%
O2 = 8%
N2 = 81%
To determine the proportions by weight, we need to convert the volumetric percentages to their corresponding weight percentages.
1. Convert CO2 to weight percentage:
CO2 has a molar mass of 44 g/mol, while the molar mass of the dry products can be assumed to be 28 g/mol (average molar mass of air). Since the sum of the percentages should be 100%, we can use the following equation to calculate the weight percentage of CO2:
CO2 weight % = CO2 volume % * (molar mass of dry products / molar mass of CO2)
CO2 weight % = 10% * (28 g/mol / 44 g/mol) = 6.36%
2. Convert CO to weight percentage:
CO has a molar mass of 28 g/mol. Using the same equation as above, we can calculate the weight percentage of CO:
CO weight % = CO volume % * (molar mass of dry products / molar mass of CO)
CO weight % = 1% * (28 g/mol / 28 g/mol) = 1%
3. Convert O2 to weight percentage:
O2 has a molar mass of 32 g/mol. Using the same equation as above, we can calculate the weight percentage of O2:
O2 weight % = O2 volume % * (molar mass of dry products / molar mass of O2)
O2 weight % = 8% * (28 g/mol / 32 g/mol) = 7%
4. Convert N2 to weight percentage:
N2 has a molar mass of 28 g/mol. Using the same equation as above, we can calculate the weight percentage of N2:
N2 weight % = N2 volume % * (molar mass of dry products / molar mass of N2)
N2 weight % = 81% * (28 g/mol / 28 g/mol) = 81%
Converting the weight percentages to proportions, we can express them in the following ratio:
CO2 : CO : O2 : N2 = 6.36 : 1 : 7 : 81
Simplifying the ratio by dividing all the values by the smallest value (1), we get:
CO2 : CO : O2 : N2 = 6.36 : 1 : 7 : 81
Multiplying all the values by 22 to eliminate the decimal point, we get:
CO2 : CO : O2 : N2 = 440 : 22 : 154 : 1782
Thus, the correct answer is option 'A': 440 : 28 : 256 : 2268.
Given:
CO2 = 10%
CO = 1%
O2 = 8%
N2 = 81%
To determine the proportions by weight, we need to convert the volumetric percentages to their corresponding weight percentages.
1. Convert CO2 to weight percentage:
CO2 has a molar mass of 44 g/mol, while the molar mass of the dry products can be assumed to be 28 g/mol (average molar mass of air). Since the sum of the percentages should be 100%, we can use the following equation to calculate the weight percentage of CO2:
CO2 weight % = CO2 volume % * (molar mass of dry products / molar mass of CO2)
CO2 weight % = 10% * (28 g/mol / 44 g/mol) = 6.36%
2. Convert CO to weight percentage:
CO has a molar mass of 28 g/mol. Using the same equation as above, we can calculate the weight percentage of CO:
CO weight % = CO volume % * (molar mass of dry products / molar mass of CO)
CO weight % = 1% * (28 g/mol / 28 g/mol) = 1%
3. Convert O2 to weight percentage:
O2 has a molar mass of 32 g/mol. Using the same equation as above, we can calculate the weight percentage of O2:
O2 weight % = O2 volume % * (molar mass of dry products / molar mass of O2)
O2 weight % = 8% * (28 g/mol / 32 g/mol) = 7%
4. Convert N2 to weight percentage:
N2 has a molar mass of 28 g/mol. Using the same equation as above, we can calculate the weight percentage of N2:
N2 weight % = N2 volume % * (molar mass of dry products / molar mass of N2)
N2 weight % = 81% * (28 g/mol / 28 g/mol) = 81%
Converting the weight percentages to proportions, we can express them in the following ratio:
CO2 : CO : O2 : N2 = 6.36 : 1 : 7 : 81
Simplifying the ratio by dividing all the values by the smallest value (1), we get:
CO2 : CO : O2 : N2 = 6.36 : 1 : 7 : 81
Multiplying all the values by 22 to eliminate the decimal point, we get:
CO2 : CO : O2 : N2 = 440 : 22 : 154 : 1782
Thus, the correct answer is option 'A': 440 : 28 : 256 : 2268.
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Volumetric analysis of sample of dry products -of combustion gave the following results: CO2 = 10% CO = 1% O2 = 8% N2 = 81%Their proportions by weight will bea)440: 28 : 256 : 2268b)22 : 14 : 256 : 1134c)440: 14: 28: 2268d)22: 28: 14: 1134Correct answer is option 'A'. Can you explain this answer?
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Volumetric analysis of sample of dry products -of combustion gave the following results: CO2 = 10% CO = 1% O2 = 8% N2 = 81%Their proportions by weight will bea)440: 28 : 256 : 2268b)22 : 14 : 256 : 1134c)440: 14: 28: 2268d)22: 28: 14: 1134Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Volumetric analysis of sample of dry products -of combustion gave the following results: CO2 = 10% CO = 1% O2 = 8% N2 = 81%Their proportions by weight will bea)440: 28 : 256 : 2268b)22 : 14 : 256 : 1134c)440: 14: 28: 2268d)22: 28: 14: 1134Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Volumetric analysis of sample of dry products -of combustion gave the following results: CO2 = 10% CO = 1% O2 = 8% N2 = 81%Their proportions by weight will bea)440: 28 : 256 : 2268b)22 : 14 : 256 : 1134c)440: 14: 28: 2268d)22: 28: 14: 1134Correct answer is option 'A'. Can you explain this answer?.
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