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ABCFED is the map of a field such that ABCD and CDEF are two trapeziums with one of the parallel sides CD common between them. Also, DE = EG, EG || FC, AG and BH are perpendicular to CD, DG = 5 cm, BH = 12 cm, BC = 15 cm, EF = 19 cm and m ∠DEG = 60°. What is the length of the perimeter of the map?
  • a)
    67 cm
  • b)
    71 cm
  • c)
    201 cm
  • d)
    213 cm
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
ABCFED is the map of a field such that ABCD and CDEF are two trapezium...
HC2 + BH2 = BC2
So HC = 9 cm.
DE = EG = DG = 5 cm ...[since DE = EG and ∠DEG = 60° making ∠DEG equilateral]
FC = EG = 5 cm ...[EF || GC and EG || FC, making EFCG a parallelogram]
EF = GC = 19 cm GH = GC - HC = 19 - 9 = 10 cm
AB = GH = 10 cm ...[ABCD is a rectangle] AD2 = AG2 + DG2 ...[Using Pythagoras Theorem in right angled ΔAGD]
AD = 13 cm
Perimeter o f the map = (AB + BC + CF + FE + ED + DA) = 10 + 15 + 5 + 19 + 5 + 1 3 = 67 cm
Hence, option 1.
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ABCFED is the map of a field such that ABCD and CDEF are two trapeziums with one of the parallel sides CD common between them. Also, DE = EG, EG || FC, AG and BH are perpendicular to CD, DG = 5 cm, BH = 12 cm, BC = 15 cm, EF = 19 cm and m ∠DEG = 60°. What is the length of the perimeter of the map?a)67 cmb)71 cmc)201 cmd)213 cmCorrect answer is option 'A'. Can you explain this answer?
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