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A magnetic moment of 1.73 BM will be shown by one among the following
  • a)
    [Cu(NH3)4]2+
  • b)
    [Ni(CN)4]2–
  • c)
    TiCl4
  • d)
    [CoCl6]4–
Correct answer is option 'A'. Can you explain this answer?
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A magnetic moment of 1.73 BM will be shown by one among the followinga...
The correct answer is Option A.
Electronic configuration of Cu2+  ion in [Cu(NH3)4]2+.
Cu2+ ion =[Ar]3d94s0.
∴Cu2+ ion has one unpaired electron.
Magnetic moment of [Cu(NH3)4]2+ (μ) = BM
where, n = no. of unpaired electrons

Whereas Ni2+ in [Ni(CN)4]2− , Ti4+ in TiCl4 and Co2+ ion [COCl6]4− has 2,0 and 3 unpaired electrons respectively.
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