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If x + (1/x) = (√3 + 1)/2, then what is the value of x2 + (1/x2)?
- a)(√3 - 2)/4
- b)(2√3 - 2)/4
- c)(2√3 - 4)/2
- d)(2√3 - 4)/4
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
If x + (1/x) = (√3 + 1)/2, then what is the value of x2+ (1/x2)?...
We have,
⇒ x + (1/x) = (√3 + 1)/2
Squaring on both sides, we get
⇒ x2 + (1/x2) + 2 = {(√3 + 1)/2}2
⇒ x2 + (1/x2) + 2 = (3 + 1 + 2√3)/4
⇒ x2 + (1/x2) = (2√3 - 4)/4
⇒ x + (1/x) = (√3 + 1)/2
Squaring on both sides, we get
⇒ x2 + (1/x2) + 2 = {(√3 + 1)/2}2
⇒ x2 + (1/x2) + 2 = (3 + 1 + 2√3)/4
⇒ x2 + (1/x2) = (2√3 - 4)/4
Most Upvoted Answer
If x + (1/x) = (√3 + 1)/2, then what is the value of x2+ (1/x2)?...
We have,
⇒ x + (1/x) = (√3 + 1)/2
Squaring on both sides, we get
⇒ x2 + (1/x2) + 2 = {(√3 + 1)/2}2
⇒ x2 + (1/x2) + 2 = (3 + 1 + 2√3)/4
⇒ x2 + (1/x2) = (2√3 - 4)/4
⇒ x + (1/x) = (√3 + 1)/2
Squaring on both sides, we get
⇒ x2 + (1/x2) + 2 = {(√3 + 1)/2}2
⇒ x2 + (1/x2) + 2 = (3 + 1 + 2√3)/4
⇒ x2 + (1/x2) = (2√3 - 4)/4
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Community Answer
If x + (1/x) = (√3 + 1)/2, then what is the value of x2+ (1/x2)?...
We have,
⇒ x + (1/x) = (√3 + 1)/2
Squaring on both sides, we get
⇒ x2 + (1/x2) + 2 = {(√3 + 1)/2}2
⇒ x2 + (1/x2) + 2 = (3 + 1 + 2√3)/4
⇒ x2 + (1/x2) = (2√3 - 4)/4
⇒ x + (1/x) = (√3 + 1)/2
Squaring on both sides, we get
⇒ x2 + (1/x2) + 2 = {(√3 + 1)/2}2
⇒ x2 + (1/x2) + 2 = (3 + 1 + 2√3)/4
⇒ x2 + (1/x2) = (2√3 - 4)/4
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Solutions for If x + (1/x) = (√3 + 1)/2, then what is the value of x2+ (1/x2)?a)(√3 - 2)/4b)(2√3 - 2)/4c)(2√3 - 4)/2d)(2√3 - 4)/4Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC.
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