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(Direction 16 - 38) Write down the correct answers. Each question carries 2 marks.
Q.Two balls are drawn from a bag containing 5 white and 7 black balls at random. What is the probability that they would be of different colours?
- a)35/66
- b)30/66
- c)12/66
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
(Direction 16 - 38)Write down the correct answers. Each question carri...
Solution:
Given, a bag contains 5 white and 7 black balls.
We need to find the probability of drawing two balls of different colours.
Total number of ways to draw two balls out of 12 balls = 12C2 = (12 × 11) / (2 × 1) = 66
Number of ways to draw two balls of different colours = Number of ways to draw one white and one black ball + Number of ways to draw one black and one white ball
= (5C1 × 7C1) + (7C1 × 5C1)
= (5 × 7) + (7 × 5)
= 35 + 35
= 70
Therefore, the probability of drawing two balls of different colours = Number of ways to draw two balls of different colours / Total number of ways to draw two balls
= 70 / 66
= 35 / 33
Hence, the correct option is (a) 35/66.
Given, a bag contains 5 white and 7 black balls.
We need to find the probability of drawing two balls of different colours.
Total number of ways to draw two balls out of 12 balls = 12C2 = (12 × 11) / (2 × 1) = 66
Number of ways to draw two balls of different colours = Number of ways to draw one white and one black ball + Number of ways to draw one black and one white ball
= (5C1 × 7C1) + (7C1 × 5C1)
= (5 × 7) + (7 × 5)
= 35 + 35
= 70
Therefore, the probability of drawing two balls of different colours = Number of ways to draw two balls of different colours / Total number of ways to draw two balls
= 70 / 66
= 35 / 33
Hence, the correct option is (a) 35/66.
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Community Answer
(Direction 16 - 38)Write down the correct answers. Each question carri...
Let white ball be W, and black ball be B,
now probability be P [(W and B)or (B and w)]
= p [(W and B) + (B and W)]
=p (W)p (B/W) + p (B)p (W/B)
= 5/12 × 7/11 + 7/12. × 5/11
= 35/132. + 35/132
=70/132. = 35/66 @ns
now probability be P [(W and B)or (B and w)]
= p [(W and B) + (B and W)]
=p (W)p (B/W) + p (B)p (W/B)
= 5/12 × 7/11 + 7/12. × 5/11
= 35/132. + 35/132
=70/132. = 35/66 @ns
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(Direction 16 - 38)Write down the correct answers. Each question carries 2 marks.Q.Two balls are drawn from a bag containing 5 white and 7 black balls at random. What is the probability that they would be of different colours?a)35/66b)30/66c)12/66d)None of theseCorrect answer is option 'A'. Can you explain this answer?
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