Class 12 Exam > Class 12 Questions > The maximum kinetic energy of photoelectrons ...
Start Learning for Free
The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts is
- a)2
- b)4
- c)6
- d)10
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The maximum kinetic energy of photoelectrons emitted from a surface wh...
Explanation:
When a photon of energy hν falls on the surface of a metal, an electron is emitted if the energy of the photon is greater than or equal to the work function of the metal.
The maximum kinetic energy of the emitted photoelectrons is given by:
K.E. max = hν - φ
where h is Planck’s constant, ν is the frequency of the incident radiation, and φ is the work function of the metal.
Given that the energy of the incident photons is 6 eV and the maximum kinetic energy of the emitted photoelectrons is 4 eV, we have:
K.E. max = 4 eV
hν = 6 eV
Substituting these values in the above equation, we get:
4 eV = 6 eV - φ
φ = 2 eV
Therefore, the work function of the metal is 2 eV.
When a potential difference (stopping potential) V is applied between the metal surface and the collector electrode, the photoelectrons are brought to rest and the maximum kinetic energy of the emitted photoelectrons is equal to the potential energy gained by the electrons in moving from the metal surface to the collector electrode.
Therefore, we have:
K.E. max = eV
where e is the electronic charge.
Substituting the value of K.E. max and e in the above equation, we get:
4 eV = eV
V = 4 V
Hence, the stopping potential is 4 volts. Therefore, option B is the correct answer.
When a photon of energy hν falls on the surface of a metal, an electron is emitted if the energy of the photon is greater than or equal to the work function of the metal.
The maximum kinetic energy of the emitted photoelectrons is given by:
K.E. max = hν - φ
where h is Planck’s constant, ν is the frequency of the incident radiation, and φ is the work function of the metal.
Given that the energy of the incident photons is 6 eV and the maximum kinetic energy of the emitted photoelectrons is 4 eV, we have:
K.E. max = 4 eV
hν = 6 eV
Substituting these values in the above equation, we get:
4 eV = 6 eV - φ
φ = 2 eV
Therefore, the work function of the metal is 2 eV.
When a potential difference (stopping potential) V is applied between the metal surface and the collector electrode, the photoelectrons are brought to rest and the maximum kinetic energy of the emitted photoelectrons is equal to the potential energy gained by the electrons in moving from the metal surface to the collector electrode.
Therefore, we have:
K.E. max = eV
where e is the electronic charge.
Substituting the value of K.E. max and e in the above equation, we get:
4 eV = eV
V = 4 V
Hence, the stopping potential is 4 volts. Therefore, option B is the correct answer.
Free Test
FREE
| Start Free Test |
Community Answer
The maximum kinetic energy of photoelectrons emitted from a surface wh...
Simply remember that the surfaces total threshold frequency=stopping potential
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer?
Question Description
The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer?.
The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer?.
Solutions for The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts isa)2b)4c)6d)10Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup