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Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will be
- a)1 : 2
- b)2 : 1
- c)1 : 4
- d)4 : 1
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Radiation of two photon energies twice and five times the work functio...
Let the maximum velocities of the photoelectrons in each case be v and u respectively and the work function of the metal be w
• Energy of photon = 2w
2w - w = mv²/2 => mv²/2 = w
• Energy of the photon = 5w
5w - w = mu²/2 => mu²/2 = 4w
On dividing,
(v/u)² = 1/4
=> v/u = 1/2
• Energy of photon = 2w
2w - w = mv²/2 => mv²/2 = w
• Energy of the photon = 5w
5w - w = mu²/2 => mu²/2 = 4w
On dividing,
(v/u)² = 1/4
=> v/u = 1/2
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Radiation of two photon energies twice and five times the work functio...
Solution:
Given:
The energies of two photons are twice and five times the work function of the metal.
To find:
The ratio of the maximum velocity of photoelectrons emitted in the two cases.
Solution:
The maximum kinetic energy of a photoelectron emitted from a metal surface is given by:
Kmax = hν - φ
where h is Planck's constant, ν is the frequency of the incident radiation and φ is the work function of the metal.
The maximum velocity of the photoelectron is given by:
vmax = √(2Kmax/m)
where m is the mass of the photoelectron.
Let the frequency of the first photon be ν1 = 2φ, and the frequency of the second photon be ν2 = 5φ.
The maximum kinetic energy of the photoelectron emitted by the first photon is:
Kmax1 = hν1 - φ = h(2φ) - φ = hφ
The maximum kinetic energy of the photoelectron emitted by the second photon is:
Kmax2 = hν2 - φ = h(5φ) - φ = 4hφ
The ratio of the maximum velocities of the photoelectrons emitted by the two photons is:
vmax2/vmax1 = √(2Kmax2/m)/√(2Kmax1/m) = √(Kmax2/Kmax1) = √(4hφ/hφ) = √4 = 2
Therefore, the ratio of the maximum velocities of the photoelectrons emitted by the two photons is 2:1.
Thus, the correct option is (a) 1:2.
Given:
The energies of two photons are twice and five times the work function of the metal.
To find:
The ratio of the maximum velocity of photoelectrons emitted in the two cases.
Solution:
The maximum kinetic energy of a photoelectron emitted from a metal surface is given by:
Kmax = hν - φ
where h is Planck's constant, ν is the frequency of the incident radiation and φ is the work function of the metal.
The maximum velocity of the photoelectron is given by:
vmax = √(2Kmax/m)
where m is the mass of the photoelectron.
Let the frequency of the first photon be ν1 = 2φ, and the frequency of the second photon be ν2 = 5φ.
The maximum kinetic energy of the photoelectron emitted by the first photon is:
Kmax1 = hν1 - φ = h(2φ) - φ = hφ
The maximum kinetic energy of the photoelectron emitted by the second photon is:
Kmax2 = hν2 - φ = h(5φ) - φ = 4hφ
The ratio of the maximum velocities of the photoelectrons emitted by the two photons is:
vmax2/vmax1 = √(2Kmax2/m)/√(2Kmax1/m) = √(Kmax2/Kmax1) = √(4hφ/hφ) = √4 = 2
Therefore, the ratio of the maximum velocities of the photoelectrons emitted by the two photons is 2:1.
Thus, the correct option is (a) 1:2.
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Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will bea)1 : 2b)2 : 1c)1 : 4d)4 : 1Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will bea)1 : 2b)2 : 1c)1 : 4d)4 : 1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will bea)1 : 2b)2 : 1c)1 : 4d)4 : 1Correct answer is option 'A'. Can you explain this answer?.
Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will bea)1 : 2b)2 : 1c)1 : 4d)4 : 1Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will bea)1 : 2b)2 : 1c)1 : 4d)4 : 1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will bea)1 : 2b)2 : 1c)1 : 4d)4 : 1Correct answer is option 'A'. Can you explain this answer?.
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Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will bea)1 : 2b)2 : 1c)1 : 4d)4 : 1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will bea)1 : 2b)2 : 1c)1 : 4d)4 : 1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Radiation of two photon energies twice and five times the work function of metal are incident sucessively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted is the two cases will bea)1 : 2b)2 : 1c)1 : 4d)4 : 1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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