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A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S is
Correct answer is '50'. Can you explain this answer?
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Verified Answer
A 20% ethanol solution is mixed with another ethanol solution, say, S ...
Let the volume of the first and the second solution be 100 and 300.
When they are mixed, quantity of ethanol in the mixture = (20 + 300S)
Let this solution be mixed with equal volume i.e. 400 of third solution in which the strength of ethanol is 20%.
So, the quantity of ethanol in the final solution = (20 + 300S + 80) = (300S + 100)
It is given that, 31.25% of 800 = (300S + 100) or, 300S + 100 = 250
Hence, 50 is the correct answer.
When they are mixed, quantity of ethanol in the mixture = (20 + 300S)
Let this solution be mixed with equal volume i.e. 400 of third solution in which the strength of ethanol is 20%.
So, the quantity of ethanol in the final solution = (20 + 300S + 80) = (300S + 100)
It is given that, 31.25% of 800 = (300S + 100) or, 300S + 100 = 250
Hence, 50 is the correct answer.
Most Upvoted Answer
A 20% ethanol solution is mixed with another ethanol solution, say, S ...
Solution:
Let us assume that the unknown concentration of solution S is x%.
Step 1: Mixing 20% ethanol solution with solution S
- Volume of 20% ethanol solution = 1
- Volume of solution S = 3
- Total volume of mixture = 4
- Therefore, the concentration of ethanol in the mixture = (0.2 x 1 + 0.x x 3)/4 = (0.2 + 0.75x)/4
Step 2: Mixing the mixture with an equal volume of 20% ethanol solution
- Volume of the mixture = 4
- Volume of 20% ethanol solution = 4
- Total volume of resultant mixture = 8
- Let the concentration of ethanol in the solution S be x%
- Concentration of ethanol in the mixture from step 1 = (0.2 + 0.75x)/4
- Concentration of ethanol in the 20% ethanol solution = 0.2
- Concentration of ethanol in the resultant mixture = 31.25%
- Therefore, (0.2 + 0.75x)/4 + 0.2 = 31.25/100
- Solving the equation, we get x = 50
Hence, the unknown concentration of solution S is 50%.
Let us assume that the unknown concentration of solution S is x%.
Step 1: Mixing 20% ethanol solution with solution S
- Volume of 20% ethanol solution = 1
- Volume of solution S = 3
- Total volume of mixture = 4
- Therefore, the concentration of ethanol in the mixture = (0.2 x 1 + 0.x x 3)/4 = (0.2 + 0.75x)/4
Step 2: Mixing the mixture with an equal volume of 20% ethanol solution
- Volume of the mixture = 4
- Volume of 20% ethanol solution = 4
- Total volume of resultant mixture = 8
- Let the concentration of ethanol in the solution S be x%
- Concentration of ethanol in the mixture from step 1 = (0.2 + 0.75x)/4
- Concentration of ethanol in the 20% ethanol solution = 0.2
- Concentration of ethanol in the resultant mixture = 31.25%
- Therefore, (0.2 + 0.75x)/4 + 0.2 = 31.25/100
- Solving the equation, we get x = 50
Hence, the unknown concentration of solution S is 50%.
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Community Answer
A 20% ethanol solution is mixed with another ethanol solution, say, S ...
Suppose A solution is 100 ml
so B is 300 ml
so C will be ( 100 + 300 + same quantity ie 400) so 80O
out of 800 total 31.25 % is ethanol so 250 ml is ethanol
a contain 20 ml, c contain (20*4)
remaining 150 ml in 300 ml so 50%
so this cal in mind, will take 30 sec at most
so B is 300 ml
so C will be ( 100 + 300 + same quantity ie 400) so 80O
out of 800 total 31.25 % is ethanol so 250 ml is ethanol
a contain 20 ml, c contain (20*4)
remaining 150 ml in 300 ml so 50%
so this cal in mind, will take 30 sec at most
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A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer?
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A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer?.
A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer?.
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A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer?, a detailed solution for A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer? has been provided alongside types of A 20% ethanol solution is mixed with another ethanol solution, say, S of unknown concentration in the proportion 1:3 by volume. This mixture is then mixed with an equal volume of 20% ethanol solution. If the resultant mixture is a 31.25% ethanol solution, then the unknown concentration of S isCorrect answer is '50'. Can you explain this answer? theory, EduRev gives you an
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