CAT Exam > CAT Questions > The strength of a salt solution is p% if 100 ...
Start Learning for Free
The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A is
- a)3 : 10
- b)1 : 3
- c)1 : 4
- d)2 : 5
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The strength of a salt solution is p% if 100 ml of the solution contai...
Let 'a', 'b' and 'c' be the concentration of salt in solutions A, B and C respectively.
It is given that three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%.
If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%.
From equation (1) and (2), we can say that
Also, on subtracting (1) from (2), we get
In solution D, B and C are mixed in the ratio 2 : 7
Hence, option B is the correct answer.
It is given that three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%.
If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%.
From equation (1) and (2), we can say that
Also, on subtracting (1) from (2), we get
In solution D, B and C are mixed in the ratio 2 : 7
Hence, option B is the correct answer.
Most Upvoted Answer
The strength of a salt solution is p% if 100 ml of the solution contai...
Given information:
- Strength of a salt solution is p% if 100 ml of the solution contains p grams of salt.
- A mixture of three salt solutions A, B, C in the proportion 1:2:3 has strength 20%.
- A mixture of the same three salt solutions in the proportion 3:2:1 has strength 30%.
- Solution D is produced by mixing B and C in the ratio 2:7.
To find: Ratio of the strength of solution D to that of solution A.
Solution:
Let's assume the following:
- The volume of solution A is a ml.
- The volume of solution B is b ml.
- The volume of solution C is c ml.
Using the given information, we can form the following equations:
- Strength of solution A = p% and volume of solution A = a ml. Therefore, the amount of salt in solution A = (p/100) * a grams.
- Strength of the resulting solution when A, B, C are mixed in the proportion 1:2:3 is 20%. Therefore, the amount of salt in the resulting solution = (20/100) * (a + 2b + 3c) grams.
- Strength of the resulting solution when A, B, C are mixed in the proportion 3:2:1 is 30%. Therefore, the amount of salt in the resulting solution = (30/100) * (3a + 2b + c) grams.
- Solution D is produced by mixing B and C in the ratio 2:7. Therefore, the volume of solution B in D = (2/9) * volume of D and the volume of solution C in D = (7/9) * volume of D. Also, the amount of salt in solution D = amount of salt in B + amount of salt in C.
Using these equations, we can solve for the unknowns and find the ratio of the strength of solution D to that of solution A:
- From the first equation, we can express the volume of solution A in terms of the amount of salt in A: a = (100/p) * amount of salt in A.
- Substituting this value of a in the second equation, we get: amount of salt in the resulting solution = (20/100) * [(100/p) * amount of salt in A + 2b + 3c] = (20/p) * amount of salt in A + (40/100) * b + (60/100) * c.
- Similarly, substituting the value of a in the third equation, we get: amount of salt in the resulting solution = (30/100) * [(300/p) * amount of salt in A + 2b + (100/p) * amount of salt in A] = (90/p) * amount of salt in A + (40/100) * b + (10/p) * amount of salt in A.
- Equating the two expressions for amount of salt in the resulting solution, we get: (20/p) * amount of salt in A + (40/100) * b + (60/100) * c = (90/p) * amount of salt in A + (40/100) * b + (10/p) * amount of salt in A.
- Simplifying and rearranging terms, we
- Strength of a salt solution is p% if 100 ml of the solution contains p grams of salt.
- A mixture of three salt solutions A, B, C in the proportion 1:2:3 has strength 20%.
- A mixture of the same three salt solutions in the proportion 3:2:1 has strength 30%.
- Solution D is produced by mixing B and C in the ratio 2:7.
To find: Ratio of the strength of solution D to that of solution A.
Solution:
Let's assume the following:
- The volume of solution A is a ml.
- The volume of solution B is b ml.
- The volume of solution C is c ml.
Using the given information, we can form the following equations:
- Strength of solution A = p% and volume of solution A = a ml. Therefore, the amount of salt in solution A = (p/100) * a grams.
- Strength of the resulting solution when A, B, C are mixed in the proportion 1:2:3 is 20%. Therefore, the amount of salt in the resulting solution = (20/100) * (a + 2b + 3c) grams.
- Strength of the resulting solution when A, B, C are mixed in the proportion 3:2:1 is 30%. Therefore, the amount of salt in the resulting solution = (30/100) * (3a + 2b + c) grams.
- Solution D is produced by mixing B and C in the ratio 2:7. Therefore, the volume of solution B in D = (2/9) * volume of D and the volume of solution C in D = (7/9) * volume of D. Also, the amount of salt in solution D = amount of salt in B + amount of salt in C.
Using these equations, we can solve for the unknowns and find the ratio of the strength of solution D to that of solution A:
- From the first equation, we can express the volume of solution A in terms of the amount of salt in A: a = (100/p) * amount of salt in A.
- Substituting this value of a in the second equation, we get: amount of salt in the resulting solution = (20/100) * [(100/p) * amount of salt in A + 2b + 3c] = (20/p) * amount of salt in A + (40/100) * b + (60/100) * c.
- Similarly, substituting the value of a in the third equation, we get: amount of salt in the resulting solution = (30/100) * [(300/p) * amount of salt in A + 2b + (100/p) * amount of salt in A] = (90/p) * amount of salt in A + (40/100) * b + (10/p) * amount of salt in A.
- Equating the two expressions for amount of salt in the resulting solution, we get: (20/p) * amount of salt in A + (40/100) * b + (60/100) * c = (90/p) * amount of salt in A + (40/100) * b + (10/p) * amount of salt in A.
- Simplifying and rearranging terms, we
Attention CAT Students!
To make sure you are not studying endlessly, EduRev has designed CAT study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CAT.
|
Explore Courses for CAT exam
|
|
Similar CAT Doubts
Top Courses for CATView all
The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer?
Question Description
The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer?.
The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer?.
Solutions for The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for CAT.
Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free.
Here you can find the meaning of The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. If three salt solutions A, B, C are mixed in the proportion 1 : 2 : 3, then the resulting solution has strength 20%. If instead the proportion is 3 : 2 : 1, then the resulting solution has strength 30%. A fourth solution, D, is produced by mixing B and C in the ratio 2 : 7. The ratio of the strength of D to that of A isa)3 : 10b)1 : 3c)1 : 4d)2 : 5Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice CAT tests.
|
|
Explore Courses for CAT exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup