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The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A is
- a)15
- b)13
- c)12
- d)14
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The strength of a salt solution is p% if 100 ml of the solution contai...
Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively.
The amount of salt in vessels A, B, C = 50 ml, 110 ml, 160 ml respectively.
The amount of water in vessels A, B, C = 450 ml, 390 ml, 340 ml respectively.
In 100 ml solution in vessel A, there will be 10ml of salt and 90 ml of water In 100 ml of solution in vessel B, there will be 22 ml of salt and 78 ml of water.
In 100 ml of solution in vessel C, there will be 32 ml of salt and 68 ml of water.
Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A
i.e after the first transfer, the amount of salt in vessels A, B, C = 40, 120, 160 ml respectively. After the second transfer, the amount of salt in vessels A, B, C =40, 98, 182 ml respectively.
After the third transfer, the amount of salt in vessels A, B, C = 72, 98, 150 respectively.
Percentage of salt in vessel A = 72 / 500 x 100
=14.4
The amount of salt in vessels A, B, C = 50 ml, 110 ml, 160 ml respectively.
The amount of water in vessels A, B, C = 450 ml, 390 ml, 340 ml respectively.
In 100 ml solution in vessel A, there will be 10ml of salt and 90 ml of water In 100 ml of solution in vessel B, there will be 22 ml of salt and 78 ml of water.
In 100 ml of solution in vessel C, there will be 32 ml of salt and 68 ml of water.
Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A
i.e after the first transfer, the amount of salt in vessels A, B, C = 40, 120, 160 ml respectively. After the second transfer, the amount of salt in vessels A, B, C =40, 98, 182 ml respectively.
After the third transfer, the amount of salt in vessels A, B, C = 72, 98, 150 respectively.
Percentage of salt in vessel A = 72 / 500 x 100
=14.4
Most Upvoted Answer
The strength of a salt solution is p% if 100 ml of the solution contai...
The question states that the strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. There are three vessels A, B, and C, each containing 500 ml of salt solution with strengths of 10%, 22%, and 32% respectively. We need to find the strength, in percentage, of the resulting solution in vessel A after the transfers.
Let's calculate the amount of salt in each vessel before the transfers:
- Vessel A contains 500 ml of a 10% solution, so it has 10% of 500 grams = 50 grams of salt.
- Vessel B contains 500 ml of a 22% solution, so it has 22% of 500 grams = 110 grams of salt.
- Vessel C contains 500 ml of a 32% solution, so it has 32% of 500 grams = 160 grams of salt.
Now, let's calculate the amount of salt in each vessel after the transfers:
- Transferring 100 ml from vessel A to vessel B does not change the amount of salt in vessel A, so it still contains 50 grams.
- Vessel B now contains 100 ml of a 10% solution, so it has 10% of 100 grams = 10 grams of salt.
- Transferring 100 ml from vessel B to vessel C does not change the amount of salt in vessel B, so it still contains 10 grams.
- Vessel C now contains 100 ml of a 22% solution, so it has 22% of 100 grams = 22 grams of salt.
- Transferring 100 ml from vessel C to vessel A does not change the amount of salt in vessel C, so it still contains 22 grams.
Finally, let's calculate the strength of the resulting solution in vessel A:
- Vessel A initially had 500 ml of a 10% solution, which contained 50 grams of salt.
- Vessel A now contains an additional 100 ml from vessel C, which contains 22 grams of salt.
- So, the total amount of salt in vessel A is 50 grams + 22 grams = 72 grams.
- The total volume of the solution in vessel A is 500 ml + 100 ml = 600 ml.
- Therefore, the strength of the resulting solution in vessel A is (72 grams / 600 ml) * 100 = 12%.
Hence, the correct answer is option D) 14%.
Let's calculate the amount of salt in each vessel before the transfers:
- Vessel A contains 500 ml of a 10% solution, so it has 10% of 500 grams = 50 grams of salt.
- Vessel B contains 500 ml of a 22% solution, so it has 22% of 500 grams = 110 grams of salt.
- Vessel C contains 500 ml of a 32% solution, so it has 32% of 500 grams = 160 grams of salt.
Now, let's calculate the amount of salt in each vessel after the transfers:
- Transferring 100 ml from vessel A to vessel B does not change the amount of salt in vessel A, so it still contains 50 grams.
- Vessel B now contains 100 ml of a 10% solution, so it has 10% of 100 grams = 10 grams of salt.
- Transferring 100 ml from vessel B to vessel C does not change the amount of salt in vessel B, so it still contains 10 grams.
- Vessel C now contains 100 ml of a 22% solution, so it has 22% of 100 grams = 22 grams of salt.
- Transferring 100 ml from vessel C to vessel A does not change the amount of salt in vessel C, so it still contains 22 grams.
Finally, let's calculate the strength of the resulting solution in vessel A:
- Vessel A initially had 500 ml of a 10% solution, which contained 50 grams of salt.
- Vessel A now contains an additional 100 ml from vessel C, which contains 22 grams of salt.
- So, the total amount of salt in vessel A is 50 grams + 22 grams = 72 grams.
- The total volume of the solution in vessel A is 500 ml + 100 ml = 600 ml.
- Therefore, the strength of the resulting solution in vessel A is (72 grams / 600 ml) * 100 = 12%.
Hence, the correct answer is option D) 14%.
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Community Answer
The strength of a salt solution is p% if 100 ml of the solution contai...
Volume of salt and water is as follows:
Initial: A=50ml salt/500ml solution, B=110/500, C=160/500.
After step I: A=40/400, B=120/600, C=160/500.
After step II: A=40/400, B=100/500, C=180/600.
After step III: A=70/500, B=100/500, C=150/500.
70/500=14%.
Initial: A=50ml salt/500ml solution, B=110/500, C=160/500.
After step I: A=40/400, B=120/600, C=160/500.
After step II: A=40/400, B=100/500, C=180/600.
After step III: A=70/500, B=100/500, C=150/500.
70/500=14%.
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The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A isa)15b)13c)12d)14Correct answer is option 'D'. Can you explain this answer?
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The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A isa)15b)13c)12d)14Correct answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A isa)15b)13c)12d)14Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A isa)15b)13c)12d)14Correct answer is option 'D'. Can you explain this answer?.
The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A isa)15b)13c)12d)14Correct answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A isa)15b)13c)12d)14Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A isa)15b)13c)12d)14Correct answer is option 'D'. Can you explain this answer?.
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