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25 ml of a solution containing NaOH and Na2CO3 required (i) 50 ml of 0.2 N HCl using phenolphthalein as an indicator (ii) 72 ml of 0.2 N HCl when titrated using methyl blue as indicator. The ratio of weight of NaOH and Na2CO3 in the solution is a) 0.48 b) 0.44 c) 0.4 d) 0.38? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 25 ml of a solution containing NaOH and Na2CO3 required (i) 50 ml of 0.2 N HCl using phenolphthalein as an indicator (ii) 72 ml of 0.2 N HCl when titrated using methyl blue as indicator. The ratio of weight of NaOH and Na2CO3 in the solution is a) 0.48 b) 0.44 c) 0.4 d) 0.38? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 25 ml of a solution containing NaOH and Na2CO3 required (i) 50 ml of 0.2 N HCl using phenolphthalein as an indicator (ii) 72 ml of 0.2 N HCl when titrated using methyl blue as indicator. The ratio of weight of NaOH and Na2CO3 in the solution is a) 0.48 b) 0.44 c) 0.4 d) 0.38?.

Solutions for 25 ml of a solution containing NaOH and Na2CO3 required (i) 50 ml of 0.2 N HCl using phenolphthalein as an indicator (ii) 72 ml of 0.2 N HCl when titrated using methyl blue as indicator. The ratio of weight of NaOH and Na2CO3 in the solution is a) 0.48 b) 0.44 c) 0.4 d) 0.38? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of 25 ml of a solution containing NaOH and Na2CO3 required (i) 50 ml of 0.2 N HCl using phenolphthalein as an indicator (ii) 72 ml of 0.2 N HCl when titrated using methyl blue as indicator. The ratio of weight of NaOH and Na2CO3 in the solution is a) 0.48 b) 0.44 c) 0.4 d) 0.38? defined & explained in the simplest way possible. Besides giving the explanation of 25 ml of a solution containing NaOH and Na2CO3 required (i) 50 ml of 0.2 N HCl using phenolphthalein as an indicator (ii) 72 ml of 0.2 N HCl when titrated using methyl blue as indicator. The ratio of weight of NaOH and Na2CO3 in the solution is a) 0.48 b) 0.44 c) 0.4 d) 0.38?, a detailed solution for 25 ml of a solution containing NaOH and Na2CO3 required (i) 50 ml of 0.2 N HCl using phenolphthalein as an indicator (ii) 72 ml of 0.2 N HCl when titrated using methyl blue as indicator. The ratio of weight of NaOH and Na2CO3 in the solution is a) 0.48 b) 0.44 c) 0.4 d) 0.38? has been provided alongside types of 25 ml of a solution containing NaOH and Na2CO3 required (i) 50 ml of 0.2 N HCl using phenolphthalein as an indicator (ii) 72 ml of 0.2 N HCl when titrated using methyl blue as indicator. The ratio of weight of NaOH and Na2CO3 in the solution is a) 0.48 b) 0.44 c) 0.4 d) 0.38? theory, EduRev gives you an ample number of questions to practice 25 ml of a solution containing NaOH and Na2CO3 required (i) 50 ml of 0.2 N HCl using phenolphthalein as an indicator (ii) 72 ml of 0.2 N HCl when titrated using methyl blue as indicator. The ratio of weight of NaOH and Na2CO3 in the solution is a) 0.48 b) 0.44 c) 0.4 d) 0.38? tests, examples and also practice JEE tests.