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Two wires of same length are shaped into a square and a circle. If they carry same current, ratio of the magnetic moment is
  • a)
    2 : π
  • b)
    4 : π
  • c)
    π : 2
  • d)
    π : 4
Correct answer is option 'D'. Can you explain this answer?
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Two wires of same length are shaped into a square and a circle. If the...
Let length of each wire is  L
For square length of each side  L/4
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Two wires of same length are shaped into a square and a circle. If the...
The magnetic moment of a current-carrying wire is given by the formula:

Magnetic moment (μ) = current (I) x area (A) x number of turns (N)

For the wire shaped into a square, the area is equal to the side length squared:

A_square = side_length^2

For the wire shaped into a circle, the area is given by the formula:

A_circle = π x radius^2

Since both wires have the same length, the perimeter of the square is equal to the circumference of the circle:

4 x side_length = 2π x radius

Simplifying the equation, we get:

side_length = (π/2) x radius

Substituting this into the area formula for the square, we get:

A_square = ((π/2) x radius)^2

Simplifying further:

A_square = (π^2/4) x radius^2

Now we can compare the areas of the square and the circle:

A_square / A_circle = ((π^2/4) x radius^2) / (π x radius^2)

The radius^2 term cancels out, leaving:

A_square / A_circle = π/4

Since the current is the same for both wires, the ratio of their magnetic moments is equal to the ratio of their areas:

M_square / M_circle = A_square / A_circle = π/4

Therefore, the ratio of the magnetic moments is 1 : (π/4), which is approximately 1 : 0.785.
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