Analysis of the circuit:
- The circuit consists of five resistors connected in series, and each resistor has a resistance of 200 ohms.
- There are two cells in the circuit, and each cell has an emf (electromotive force) of 3 volts.
- The open circuit voltage is denoted as x/10 volts.

Calculating the total resistance:
- Since the resistors are connected in series, the total resistance in the circuit can be calculated by summing up the individual resistances.
- In this case, the total resistance is 5 times the resistance of each resistor, which is 5 * 200 ohms = 1000 ohms.

Calculating the current:
- The current flowing through the circuit is given by Ohm's Law, which states that current (I) is equal to the voltage (V) divided by the resistance (R): I = V/R.
- In this case, the total voltage across the circuit is the sum of the emfs of the two cells, which is 3 + 3 = 6 volts.
- Therefore, the current flowing through the circuit is 6 volts divided by 1000 ohms, which is 0.006 amperes.

Calculating the open circuit voltage:
- The open circuit voltage is the voltage across the terminals of the circuit when no current is flowing through it.
- In this case, the open circuit voltage is equal to the voltage across the two cells.
- Since each cell has an emf of 3 volts, the open circuit voltage is 3 + 3 = 6 volts.

Calculating x:
- The question states that the open circuit voltage is x/10 volts.
- Therefore, x/10 = 6 volts.
- Multiplying both sides of the equation by 10 gives x = 6 * 10 = 60 volts.

Final answer:
- The value of x is 60 volts.
- However, the question asks for x/10, so the final answer is 60/10 = 6 volts.

Conclusion:
- The correct answer is '6'.