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The capacity of a parallel plate condenser is 10 μ Fd without dielectric. After that, a dielectric of constant 2 is used to fill half thickness between the plates of another capacitor of same capacitance. The net capacitance after joining both of them in series in μ Fd is
  • a)
    10
  • b)
    20
  • c)
    15
  • d)
    13.33
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The capacity of a parallel plate condenser is 10 μ Fd without diele...
Initial c = 10 
let capacitance of capictor with dielectric is C1 and without dielectric is ç2 
finally they are connected in series 
therefore Ceq= C1*C2/(C1+C2)
C1=2*10*2=40
C2=10*2=20
Hence Ceq = 40*20/(20+40)
800/60
=13.33.
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Most Upvoted Answer
The capacity of a parallel plate condenser is 10 μ Fd without diele...
The capacity of a parallel plate condenser is typically measured in farads (F). However, it seems that the value provided in your question is incomplete. Could you please provide the missing information?
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The capacity of a parallel plate condenser is 10 μ Fd without dielectric. After that, a dielectric of constant 2 is used to fill half thickness between the plates of another capacitor of same capacitance. The net capacitance after joining both of them in series in μ Fd isa)10b)20c)15d)13.33Correct answer is option 'D'. Can you explain this answer?
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