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A particle is thrown upwards at the velocity of 39.2 m/sec. Time to reach the highest point is
  • a)
    3 seconds
  • b)
    4 seconds
  • c)
    3.75 seconds
  • d)
    4.75 seconds
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A particle is thrown upwards at the velocity of 39.2 m/sec. Time to re...
initial velocity=u= 39.2 m/s
final velocity=v= 0 m/s
acceleration due to gravity=g=-9.8m/s2
We know that, v = u + gt
On substituting the above values, we get
t=4 s
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Most Upvoted Answer
A particle is thrown upwards at the velocity of 39.2 m/sec. Time to re...
To determine the time taken by the particle to reach the highest point, we can use the following formula of motion:

v = u + at

where:
v = final velocity (0 m/s at the highest point)
u = initial velocity (39.2 m/s)
a = acceleration (acceleration due to gravity, which is -9.8 m/s^2 for upward motion)
t = time taken

We need to rearrange the formula to solve for t:

t = (v - u) / a

Substituting the given values:

t = (0 - 39.2) / -9.8
t = 39.2 / 9.8
t = 4 seconds

Therefore, the correct answer is option 'B' which states that it takes 4 seconds for the particle to reach the highest point.

Here is a summary of the solution:

- Given: initial velocity (u) = 39.2 m/s
- To find: time taken (t) to reach the highest point
- Formula: t = (v - u) / a
- Substituting values: t = (0 - 39.2) / -9.8
- Simplifying: t = 39.2 / 9.8
- Calculating: t = 4 seconds
- Therefore, the correct answer is option 'B' which states 4 seconds.
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A particle is thrown upwards at the velocity of 39.2 m/sec. Time to reach the highest point isa)3 secondsb)4 secondsc)3.75 secondsd)4.75 secondsCorrect answer is option 'B'. Can you explain this answer?
Question Description
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