How many pairs (m, n) of positive integers satisfy the equation m2 + 1...
n2 − m2 = 105
(n - m)(n + m) = 1*105, 3*35, 5*21, 7*15, 15*7, 21*5, 35*3, 105*1.
n - m = 1, n + m = 105 ==> n = 53, m = 52
n - m = 3, n + m = 35 ==> n = 19, m = 16
n - m = 5, n + m = 21 ==> n = 13, m = 8
n - m = 7, n + m = 15 ==> n = 11, m = 4
n - m = 15, n + m = 7 ==> n = 11, m = -4
n - m = 21, n + m = 5 ==> n = 13, m = -8
n - m = 35, n + m = 3 ==> n = 19, m = -16
n - m = 105, n + m = 1 ==> n = 53, m = -52
Since only positive integer values of m and n are required. There are 4 possible solutions.
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How many pairs (m, n) of positive integers satisfy the equation m2 + 1...
Given:
The equation is m^2 - 105 = n^2.
To find:
The number of pairs (m, n) of positive integers that satisfy the equation.
Solution:
To solve this problem, let's analyze the equation step by step.
Step 1:
Rearranging the equation, we get:
m^2 - n^2 = 105
Step 2:
We can further simplify the equation using the difference of squares formula:
(m + n)(m - n) = 105
Step 3:
Now, we need to find all the factors of 105 and pair them up in such a way that their difference is an even number.
The factors of 105 are:
1, 3, 5, 7, 15, 21, 35, 105
Step 4:
Let's pair up the factors:
(1, 105), (3, 35), (5, 21), (7, 15)
Step 5:
Now, we need to find the values of m and n for each pair of factors.
For the first pair (1, 105), we have:
m + n = 105
m - n = 1
Adding the two equations, we get:
2m = 106
m = 53
Substituting the value of m in one of the equations, we get:
53 + n = 105
n = 52
Therefore, the pair (m, n) is (53, 52).
Step 6:
Similarly, we can find the values of m and n for the other pairs of factors:
For the pair (3, 35), we have:
m + n = 35
m - n = 3
Adding the two equations, we get:
2m = 38
m = 19
Substituting the value of m in one of the equations, we get:
19 + n = 35
n = 16
Therefore, the pair (m, n) is (19, 16).
Step 7:
For the pair (5, 21), we have:
m + n = 21
m - n = 5
Adding the two equations, we get:
2m = 26
m = 13
Substituting the value of m in one of the equations, we get:
13 + n = 21
n = 8
Therefore, the pair (m, n) is (13, 8).
Step 8:
For the pair (7, 15), we have:
m + n = 15
m - n = 7
Adding the two equations, we get:
2m = 22
m = 11
Substituting the value of m in one of the equations, we get:
11 + n = 15
n = 4
Therefore, the pair (m, n) is (11, 4).
Step 9:
Thus, there are a total of 4 pairs (m, n) of positive integers that satisfy the equation m^2 - 105 = n^2. These pairs are: