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In isoceles triangle height is 8cm and perimeter vof triangle is 64cm find the area of triangle?
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In isoceles triangle height is 8cm and perimeter vof triangle is 64cm ...
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In isoceles triangle height is 8cm and perimeter vof triangle is 64cm ...
Problem Statement

In an isosceles triangle, the height is 8cm and the perimeter of the triangle is 64cm. Find the area of the triangle.


Solution

Let's label the triangle as ABC, where AC = BC and AD is the height of the triangle.

We know that the perimeter of the triangle is the sum of all its sides, so:

Perimeter = AB + AC + BC = 2AC + AB = 64cm

Since we know that AC = BC, we can substitute AC for BC in the equation:

Perimeter = 2AC + AB = 64cm

2AC + AB = 64cm

Now, we need to use the fact that the height of the triangle is 8cm to find the length of AB. The height of the triangle divides the base AB into two equal parts. Let's label the midpoint of AB as D.

Using the Pythagorean theorem on triangle ABD, we get:

AD^2 + BD^2 = AB^2

8^2 + (AB/2)^2 = AB^2

Simplifying the equation, we get:

64 + AB^2/4 = AB^2

3AB^2/4 = 64

AB^2 = 256/3

AB = sqrt(256/3)

AB ≈ 9.237cm

Now that we know the length of AB, we can find the length of AC:

Perimeter = 2AC + AB = 64cm

2AC + 9.237 ≈ 64cm

2AC ≈ 54.763

AC ≈ 27.3815cm

Now that we know the lengths of AB and AC, we can calculate the area of the triangle using the formula:

Area = (1/2) x base x height

Area = (1/2) x AB x AD

Area = (1/2) x 9.237 x 8

Area ≈ 36.948cm^2


Answer

The area of the isosceles triangle is approximately 36.948cm^2.
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In isoceles triangle height is 8cm and perimeter vof triangle is 64cm find the area of triangle?
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