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2-Methylpropane on monochlorination under photochemical condition give
- a)2-Chloro-2-methylpropane as major product
- b)(1:1) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropane
- c)1-Chloro-2-methylpropane as a major product
- d)(1:9) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropane
Correct answer is option 'C'. Can you explain this answer?
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2-Methylpropane on monochlorination under photochemical condition give...
Ratio of A: B is 5:9
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2-Methylpropane on monochlorination under photochemical condition give...
Monochlorination of 2-Methylpropane under Photochemical Conditions
The monochlorination of 2-methylpropane under photochemical conditions refers to the substitution of one hydrogen atom in 2-methylpropane with a chlorine atom in the presence of light. This reaction is an example of free radical halogenation.
Radical Formation
- Initially, a chlorine molecule (Cl2) absorbs energy from light, which causes the bond between the chlorine atoms to break homolytically, forming two chlorine radicals (Cl•).
Initiation
- One chlorine radical (Cl•) reacts with 2-methylpropane to form a methyl radical (CH3•) and HCl.
- This reaction is the initiation step of the reaction mechanism.
Propagation
- The methyl radical (CH3•) reacts with a chlorine molecule (Cl2) to form chloromethane (CH3Cl) and a chlorine radical (Cl•).
- The chlorine radical (Cl•) reacts with another molecule of 2-methylpropane to form 1-chloro-2-methylpropane and a methyl radical (CH3•).
- These reactions are the propagation steps of the reaction mechanism.
Termination
- The radical species can undergo various termination steps, where two radicals combine to form a stable molecule.
- Possible termination steps include the combination of two methyl radicals (CH3• + CH3•) to form ethane (C2H6) and the combination of a methyl radical and a chlorine radical (CH3• + Cl•) to form chloromethane (CH3Cl).
Products
- The major product of the monochlorination of 2-methylpropane under photochemical conditions is 1-chloro-2-methylpropane.
- This is because the reaction proceeds via a radical mechanism, and the propagation step involving the formation of 1-chloro-2-methylpropane is more favorable due to the stability of the resulting radical intermediate.
- The other possible product, 2-chloro-2-methylpropane, is formed via a different propagation step and is therefore present in smaller amounts.
- The formation of other products, such as chloromethane and ethane, is also possible but in much smaller quantities.
Conclusion
The monochlorination of 2-methylpropane under photochemical conditions predominantly yields 1-chloro-2-methylpropane as the major product. This is due to the favorable propagation step leading to the formation of this product. However, a small amount of 2-chloro-2-methylpropane and other byproducts may also be formed.
The monochlorination of 2-methylpropane under photochemical conditions refers to the substitution of one hydrogen atom in 2-methylpropane with a chlorine atom in the presence of light. This reaction is an example of free radical halogenation.
Radical Formation
- Initially, a chlorine molecule (Cl2) absorbs energy from light, which causes the bond between the chlorine atoms to break homolytically, forming two chlorine radicals (Cl•).
Initiation
- One chlorine radical (Cl•) reacts with 2-methylpropane to form a methyl radical (CH3•) and HCl.
- This reaction is the initiation step of the reaction mechanism.
Propagation
- The methyl radical (CH3•) reacts with a chlorine molecule (Cl2) to form chloromethane (CH3Cl) and a chlorine radical (Cl•).
- The chlorine radical (Cl•) reacts with another molecule of 2-methylpropane to form 1-chloro-2-methylpropane and a methyl radical (CH3•).
- These reactions are the propagation steps of the reaction mechanism.
Termination
- The radical species can undergo various termination steps, where two radicals combine to form a stable molecule.
- Possible termination steps include the combination of two methyl radicals (CH3• + CH3•) to form ethane (C2H6) and the combination of a methyl radical and a chlorine radical (CH3• + Cl•) to form chloromethane (CH3Cl).
Products
- The major product of the monochlorination of 2-methylpropane under photochemical conditions is 1-chloro-2-methylpropane.
- This is because the reaction proceeds via a radical mechanism, and the propagation step involving the formation of 1-chloro-2-methylpropane is more favorable due to the stability of the resulting radical intermediate.
- The other possible product, 2-chloro-2-methylpropane, is formed via a different propagation step and is therefore present in smaller amounts.
- The formation of other products, such as chloromethane and ethane, is also possible but in much smaller quantities.
Conclusion
The monochlorination of 2-methylpropane under photochemical conditions predominantly yields 1-chloro-2-methylpropane as the major product. This is due to the favorable propagation step leading to the formation of this product. However, a small amount of 2-chloro-2-methylpropane and other byproducts may also be formed.
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2-Methylpropane on monochlorination under photochemical condition givea)2-Chloro-2-methylpropane as major productb)(1:1) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropanec)1-Chloro-2-methylpropane as a major productd)(1:9) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropaneCorrect answer is option 'C'. Can you explain this answer?
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2-Methylpropane on monochlorination under photochemical condition givea)2-Chloro-2-methylpropane as major productb)(1:1) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropanec)1-Chloro-2-methylpropane as a major productd)(1:9) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropaneCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 2-Methylpropane on monochlorination under photochemical condition givea)2-Chloro-2-methylpropane as major productb)(1:1) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropanec)1-Chloro-2-methylpropane as a major productd)(1:9) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropaneCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2-Methylpropane on monochlorination under photochemical condition givea)2-Chloro-2-methylpropane as major productb)(1:1) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropanec)1-Chloro-2-methylpropane as a major productd)(1:9) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropaneCorrect answer is option 'C'. Can you explain this answer?.
2-Methylpropane on monochlorination under photochemical condition givea)2-Chloro-2-methylpropane as major productb)(1:1) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropanec)1-Chloro-2-methylpropane as a major productd)(1:9) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropaneCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 2-Methylpropane on monochlorination under photochemical condition givea)2-Chloro-2-methylpropane as major productb)(1:1) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropanec)1-Chloro-2-methylpropane as a major productd)(1:9) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropaneCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2-Methylpropane on monochlorination under photochemical condition givea)2-Chloro-2-methylpropane as major productb)(1:1) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropanec)1-Chloro-2-methylpropane as a major productd)(1:9) Mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropaneCorrect answer is option 'C'. Can you explain this answer?.
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