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Let f(θ) = (1+sin2θ)(2–sin2θ). Then for all values of θ
  • a)
    f(θ) > 9/4
  • b)
    f(θ) <2
  • c)
    f(θ)> 11/4
  • d)
    2≤ f(θ)≤ 9/4
Correct answer is option 'D'. Can you explain this answer?
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Let f(θ) = (1+sin2θ)(2–sin2θ). Then for all va...
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Let f(θ) = (1+sin2θ)(2–sin2θ). Then for all values of θa)f(θ) > 9/4b)f(θ) <2c)f(θ)> 11/4d)2≤ f(θ)≤ 9/4Correct answer is option 'D'. Can you explain this answer?
Question Description
Let f(θ) = (1+sin2θ)(2–sin2θ). Then for all values of θa)f(θ) > 9/4b)f(θ) <2c)f(θ)> 11/4d)2≤ f(θ)≤ 9/4Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let f(θ) = (1+sin2θ)(2–sin2θ). Then for all values of θa)f(θ) > 9/4b)f(θ) <2c)f(θ)> 11/4d)2≤ f(θ)≤ 9/4Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let f(θ) = (1+sin2θ)(2–sin2θ). Then for all values of θa)f(θ) > 9/4b)f(θ) <2c)f(θ)> 11/4d)2≤ f(θ)≤ 9/4Correct answer is option 'D'. Can you explain this answer?.
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