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A man of 60 kg gains 1000 cal of heat by eating 5 mangoes. His efficiency is 56 percentage. To what height he can jump by using this energy?
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A man of 60 kg gains 1000 cal of heat by eating 5 mangoes. His efficie...
Calculation of Jump Height using Energy from Mangoes


Given Information:


  • Mass of the man = 60 kg

  • Heat gained by eating 5 mangoes = 1000 cal

  • Efficiency of the man = 56%



Calculation of Energy Gained by the Man

The energy gained by the man from eating 5 mangoes can be calculated using the formula:

Energy gained = Heat gained x Efficiency

Substituting the given values, we get:

Energy gained = 1000 cal x 0.56

Energy gained = 560 cal


Calculation of Potential Energy of the Man

The potential energy of the man can be calculated using the formula:

Potential Energy = Mass x Gravity x Height

Assuming that the man jumps vertically, the potential energy can be equated to the energy gained from eating the mangoes. Hence, we get:

Mass x Gravity x Height = Energy gained

Substituting the given values, we get:

60 kg x 9.8 m/s^2 x Height = 560 cal x 4.184 J/cal

Height = 560 x 4.184 / (60 x 9.8)

Height = 3.01 meters


Conclusion

Therefore, the man can jump up to a height of 3.01 meters using the energy gained from eating 5 mangoes, assuming that all the energy is converted to potential energy. However, in reality, some of the energy will be lost as heat and sound during the jump, and hence the actual jump height will be lower than the calculated value.
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A man of 60 kg gains 1000 cal of heat by eating 5 mangoes. His efficie...
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A man of 60 kg gains 1000 cal of heat by eating 5 mangoes. His efficiency is 56 percentage. To what height he can jump by using this energy?
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