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Two spheres of the same material, but of radii R and 3R are allowed to fall vertically downwards through a liquid of density σ. The ratio of their terminal velocities is
  • a)
    1 : 3
  • b)
    1 : 6
  • c)
    1 : 9
  • d)
    1 : 1
Correct answer is option 'C'. Can you explain this answer?
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Let's assume the density of the liquid is ρ.

When a sphere falls through a liquid, it experiences two forces: the gravitational force and the buoyant force.

The gravitational force acting on a sphere is given by the equation:

F_gravity = (4/3)πR^3ρg

where g is the acceleration due to gravity.

The buoyant force acting on a sphere is given by the equation:

F_buoyant = (4/3)πR^3ρ_lg

where ρ_l is the density of the liquid.

Since both spheres are made of the same material, their densities are the same. Therefore, the gravitational forces acting on both spheres are equal.

F_gravity1 = F_gravity2

(4/3)πR^3ρg = (4/3)π(3R)^3ρg

R^3ρg = (27R^3)ρg

R^3 = 27R^3

R = 3R

This means that the radius of the smaller sphere is one-third of the radius of the larger sphere.

In other words, the radius of the smaller sphere is R, and the radius of the larger sphere is 3R.
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Two spheres of the same material, but of radii R and 3R are allowed to fall vertically downwards through a liquid of density σ. The ratio of their terminal velocities isa)1 : 3b)1 : 6c)1 : 9d)1 : 1Correct answer is option 'C'. Can you explain this answer?
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