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If α, β are the roots of the quadratic equation x2+ax+b=0, (b≠0); then the quadratic equation whose roots areα - 1/β,β - 1/αa)ax2+a(b–1)x+(a–1)2=0b)bx2+a(b–1)x+(b–1)2=0c)x2+ax+b = 0d)abx2+bx+a = 0Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about If α, β are the roots of the quadratic equation x2+ax+b=0, (b≠0); then the quadratic equation whose roots areα - 1/β,β - 1/αa)ax2+a(b–1)x+(a–1)2=0b)bx2+a(b–1)x+(b–1)2=0c)x2+ax+b = 0d)abx2+bx+a = 0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for If α, β are the roots of the quadratic equation x2+ax+b=0, (b≠0); then the quadratic equation whose roots areα - 1/β,β - 1/αa)ax2+a(b–1)x+(a–1)2=0b)bx2+a(b–1)x+(b–1)2=0c)x2+ax+b = 0d)abx2+bx+a = 0Correct answer is option 'B'. Can you explain this answer?.
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Here you can find the meaning of If α, β are the roots of the quadratic equation x2+ax+b=0, (b≠0); then the quadratic equation whose roots areα - 1/β,β - 1/αa)ax2+a(b–1)x+(a–1)2=0b)bx2+a(b–1)x+(b–1)2=0c)x2+ax+b = 0d)abx2+bx+a = 0Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
If α, β are the roots of the quadratic equation x2+ax+b=0, (b≠0); then the quadratic equation whose roots areα - 1/β,β - 1/αa)ax2+a(b–1)x+(a–1)2=0b)bx2+a(b–1)x+(b–1)2=0c)x2+ax+b = 0d)abx2+bx+a = 0Correct answer is option 'B'. Can you explain this answer?, a detailed solution for If α, β are the roots of the quadratic equation x2+ax+b=0, (b≠0); then the quadratic equation whose roots areα - 1/β,β - 1/αa)ax2+a(b–1)x+(a–1)2=0b)bx2+a(b–1)x+(b–1)2=0c)x2+ax+b = 0d)abx2+bx+a = 0Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of If α, β are the roots of the quadratic equation x2+ax+b=0, (b≠0); then the quadratic equation whose roots areα - 1/β,β - 1/αa)ax2+a(b–1)x+(a–1)2=0b)bx2+a(b–1)x+(b–1)2=0c)x2+ax+b = 0d)abx2+bx+a = 0Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice If α, β are the roots of the quadratic equation x2+ax+b=0, (b≠0); then the quadratic equation whose roots areα - 1/β,β - 1/αa)ax2+a(b–1)x+(a–1)2=0b)bx2+a(b–1)x+(b–1)2=0c)x2+ax+b = 0d)abx2+bx+a = 0Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.